如何在linux中覆盖变量值 [英] How to overwrite variable value in linux

问题描述

我想将变量s1的值从abc覆盖到---> [更多/ home / mohsin / Desktop / system_usage_bash_file | grep TIME | awk'BEGIN {FS =，} {print $ 3}']



但是当我回声时我在两个回声上得到abc，意味着它没有被覆盖



我尝试了什么：



＃！/ bin / bash

s1 =abc

s2 =USED

echobefore

echo $ s1

s1 = more / home / mohsin / Desktop / system_usage_bash_file | grep TIME | awk'BEGIN {FS =，} {print $ 3}'

echoafter

echo $ s1

解决方案

3}']



但是当我回声时我在两个回声上得到abc，意味着它没有被覆盖



我尝试过：



＃！/ bin / bash

s1 =abc

s2 =USED

echobefore

echo

s1

s1 = more / home / mohsin / Desktop / system_usage_bash_file | grep TIME | awk'BEGIN {FS =，} {print

3}'

echoafter

echo

i want to overwrite value of variable s1 from "abc" to ---> [more /home/mohsin/Desktop/system_usage_bash_file | grep TIME | awk 'BEGIN {FS=","} {print $3}']

but when i echo i get "abc" on both echos,means it is not overwritten

What I have tried:

#!/bin/bash
s1="abc"
s2="USED"
echo "before"
echo $s1
s1= more /home/mohsin/Desktop/system_usage_bash_file | grep TIME | awk 'BEGIN {FS=","} {print $3}'
echo "after"
echo $s1

解决方案

3}']

but when i echo i get "abc" on both echos,means it is not overwritten

What I have tried:

#!/bin/bash
s1="abc"
s2="USED"
echo "before"
echo

s1
s1= more /home/mohsin/Desktop/system_usage_bash_file | grep TIME | awk 'BEGIN {FS=","} {print

3}'
echo "after"
echo

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