将char数组参数传递给function [英] Pass char array arguments to function

问题描述

大家好吧

我需要知道如何传递char数组的元素，例如

argv [0] =。/ run_single_zone

argv [1] =data_pub / my_net.xml

argv [2] =data_pub / zone.xml

argv [3] = my_output.xml

argv [4] =[z< = 10]

到它取一个整数和数组的函数，我的函数是

run_single_zone（argc，argv []）;

谢谢所有

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我的尝试：



i不知道非常

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Hi every body
I need to know how I can pass an char array's elements such as
argv[0] = "./run_single_zone"
argv[1] = "data_pub/my_net.xml"
argv[2] = "data_pub/zone.xml"
argv[3] = "my_output.xml"
argv[4] = "[z <= 10]"
to the function which it take an integer and array, my function is
run_single_zone(argc, argv[]);
thanks all
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What I have tried:

i don't know very much
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推荐答案

当您使用C ++时，您可能听说过 main 函数 - 应用程序的入口点......

现在，如果你看一下主要文件 [ ^ ]，您将看到它能够接收字符串数组......

As you are working with C++, you probably heard of the main function - the entry point of your application...
Now if you look at the documentation of main[^], you will see that it is able to receive an array of strings...

int main (int argc, char* argv[])

从那里你可以知道 run_single_zone 的签名应该是这样的：

From there you can learn that run_single_zone's signature should be something like this:

run_single_zone(int argc, char* argv[]);

（总是很好看的您正在使用的语言的文档...就像关于点的章节一样ers和数组）

(It is always good to read the documentation of a language you are using...like the chapters about pointers and arrays)

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