我想知道char变量的每个int值... [英] I want to know the each int value to char variable...

问题描述

例如：

CString ip_address = _T（192.168.0.213）;



我想知道要移动的方法每个char值为192,168,0,213的每个char变量大小为1.



喜欢这个：





char ipaddr [4];



ipaddr [0] = 192;



ipaddr [1] = 168;



ipaddr [1] = 0;



ipaddr [1] = 213;



是的，我真正知道的是数据类型转换CString（或char字符串）的方法

整数变量。



谢谢。



我尝试了什么：



在这个晚上，这个问题浪费了3-4个小时。

For example:
CString ip_address = _T("192.168.0.213");

I want to know the method to move each int value 192,168,0,213 to each of char variable with size 1.

Like this:


char ipaddr[4];

ipaddr[0] = 192;

ipaddr[1] = 168;

ipaddr[1] = 0;

ipaddr[1] = 213;

Yes, What I really know is the method of the datatype conversion CString(or char string) to
integer variables.

Thank you.

What I have tried:

In this evening, 3-4 more hours wasted for this problem.

推荐答案

这个已经多次询问和回答。这只是找到正确搜索词的问题。我使用了c ++ parse ip string并得到了很多有用的结果：

C ++如何将ip地址转换为字节？ - 堆栈溢出 [ ^ ]

c - 以4个单字节解析ip地址字符串 - Stack Overflow [ ^ ]



一旦选择了解析方法，就必须注意到你的字符串是 CString （ TCHAR * ）。因此，请使用C标准库的 _t * 版本（例如 _stscanf ）。因为大多数字符串到整数转换返回一个整数，所以在分配时必须将它们转换为字节。



使用 sscanf的示例 / _stscanf ：

This has been asked and answered multiple times. It is just a question of finding the correct search term. I used "c++ parse ip string" and got a lot of useful results:
C++ how to convert ip address to bytes? - Stack Overflow[^]
c - parsing ip adress string in 4 single bytes - Stack Overflow[^]

Once you have choosen a parsing method you must observe that your string is CString (TCHAR *). Therefore, use the _t* versions of the C standard library (e.g. _stscanf). Because most string to integer conversions return an integer, you must cast them to bytes when assigning.

Example using sscanf / _stscanf:

unsigned short a, b, c, d;
// May check the return value here (should be 4) for basic validity check
_stscanf(ip_address.GetString(), _T("%hu.%hu.%hu.%hu"), &a, &b, &c, &d);
unsigned char ipaddr[4];
ipaddr[0] = static_cast<unsigned char>(a);
ipaddr[1] = static_cast<unsigned char>(b);
ipaddr[2] = static_cast<unsigned char>(c);
ipaddr[3] = static_cast<unsigned char>(d);

有几种方法可以完成这样的任务。例如，您可以使用 Tokenize [ ^ ]方法提取octects的所有（字符串表示）然后转换每个字符串到相应的字节（例如使用 itoa [ ^ ]。

There are several ways to accomplish such a task. You can, for instance, use the Tokenize[^] method to extract all (the string representations of) the octects ant then convert each string to the corresponding byte (e.g. using itoa[^]).

拆分每个字符串逗号，并使用您已经知道的每个部分的数据类型转换。然后将整数值转换为一个字节（或unsigned char）并将四个元素分配给你的ipaddr数组。

但是不要将它声明为char - 这是一个带符号的7位数量和IP地址元素是无符号的8位值，应该这样处理。

小错别字[/ edit]

Split the string at each comma, and use the datatype conversion you already know about on each part. Then just cast the integer value to a byte (or unsigned char) and assign to the four elements to your ipaddr array.
But don't declare it as char - that's a signed 7 bit quantity and IP address elements are unsigned 8 bit values and should be treated as such.
[edit]Minor typos[/edit]

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