如何在数组中进行对象序列化？ [英] How do I do object serialization in an array?

问题描述

java 18错误

FileInputStream t = new FileInputStream（D：\\ abc.txt）



我尝试过：



包装序列号;



import java.io.Serializable;



public class serial implements Serializable {

public String name;

public String地址;

public String PhoneNo;



}



主要班级

包序列;



import java.io.FileInputStream;

import java.io.FileNotFoundException;

import java.io.FileOutputStream;

import java.io.IOException;

import java.io.ObjectInputStream;

import java.io.ObjectOutputStream;



public class main {



public static void main （String [] args）抛出IOException，ClassNotFoundException {

// TODO自动生成的方法stub

serial [] X = new serial [10];

for（int i = 0; i< x.length; i ++）>

{



if（i == 1）

{

X [i] = new serial（）;

X [i] .name =ajay;

X [i] .address =delhi;

X [i] .PhoneNo = 78748;





}

其他

{

X [i] = new serial（）;

X [i] .name =abc;

X [i] .address = xyz;

X [i] .PhoneNo =1646;



}



}





FileOutputStream p = new FileOutputStream（D：\\ abc.txt）;

ObjectOutputStream pp = new ObjectOutputStream（p）;

pp.writeObject（X）;



FileInputStream t = new FileInputStream（D：\\ abc.txt）;



ObjectInputStream tt = new ObjectInputStream（t）;

serial [] ll =（serial []）tt.readObject（）;

for（int i = 0; i< ll.length; i ++）>

{

System.out.println（ll [i] .name）;

System.out.println（ll [i] .address）;

System.out.println（ll [i] .PhoneNo）;



}



}



}

java 18 error on the line inputstream
FileInputStream t = new FileInputStream("D:\\abc.txt")

What I have tried:

package serial;

import java.io.Serializable;

public class serial implements Serializable{
public String name;
public String address;
public String PhoneNo;

}

"main class"
package serial;

import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.ObjectInputStream;
import java.io.ObjectOutputStream;

public class main {

public static void main(String[] args) throws IOException, ClassNotFoundException {
// TODO Auto-generated method stub
serial [] X= new serial[10];
for(int i=0;i<x.length;i++)>
{

if(i==1)
{
X[i]=new serial();
X[i].name ="ajay";
X[i].address = "delhi";
X[i].PhoneNo = "78748";


}
else
{
X[i]=new serial();
X[i].name ="abc";
X[i].address = "xyz";
X[i].PhoneNo = "1646";

}

}


FileOutputStream p = new FileOutputStream ("D:\\abc.txt");
ObjectOutputStream pp= new ObjectOutputStream (p);
pp.writeObject(X);

FileInputStream t = new FileInputStream("D:\\abc.txt");

ObjectInputStream tt = new ObjectInputStream(t);
serial[] ll = (serial[]) tt.readObject();
for(int i=0;i<ll.length;i++)>
{
System.out.println(ll[i].name);
System.out.println(ll[i].address);
System.out.println(ll[i].PhoneNo);

}

}

}

推荐答案

您正在尝试在关闭输出流之前打开输入流，因此该文件不存在于任何可用的形式中。在打开输入之前，只需添加

You are trying to open the input stream before you have closed the output stream, so the file does not exist in any usable form. Just add

p.close()

。

before you open the input.

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