使用正则表达式选择括号 [英] Using regex to select the brackets
问题描述
目标:
如果(+)内的数据包含字母和包含括号的数据,那么它就是真的。
但是如果它包含任何数字的数据,包括括号,那么它将是假的。
问题:
我不知道如何解决它包括括号。
http://regexr.com/3d0dh
通过查看代码,选择不包括括号
谢谢!
sdf(ff)
回答: true
dddd(335g)ddd
答案: false
sdf(f344f )21ff
回答: false
sdf(dd)433dd
回答: true
我尝试过:
我编写了正则表达式代码,我也做了一些研究,但不幸的是我仍然找不到答案或部分答案。
< blockq uote>试试这个:
\([a-zA-Z] + \)
学习: 30分钟正则表达式教程 [ ^ ]
Goal:
If the data inside of the "(" + ")" contains data that is alphabet and included brackets, then it is true.
However if it contain data that is any number, included brackets, then it will be false.
Problem:
I don't know how to solve it in relation to including brackets.
http://regexr.com/3d0dh
By reviewing the code, the selection does not include the brackets
Thank you!
sdf (ff)
answer: true
dddd (335g) ddd
answer: false
sdf(f344f) 21ff
answer: false
sdf(dd) 433dd
answer: true
What I have tried:
I have coded the regex code and I also have made some research but unfortunatly I still cannot find the answer or part of the answer.
Try this:
\([a-zA-Z]+\)
Learn: The 30 Minute Regex Tutorial[^]
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