如何提供链接提交按钮和网格视图链接按钮 [英] How Can I Give Link To Submit Button And Grid View Linkbutton
问题描述
我有以下gridview下载选项（链接按钮），当我点击下载我发送otp到手机，
然后输入otp然后提交和下载应该开始
我的问题是
当我提交otp下载应该开始，
我怎么能给链接提交按钮和网格视图linkbutton
aspx代码
< pre lang =HTML> < asp：GridView ID = GridView1 runat = server HeaderStyle-BackColor = #cccccc HeaderStyle-ForeColor = 黑色
< span class =code-attribute> RowStyle-BackColor = white RowStyle-ForeColor = ＃003366 AlternatingRowStyle-BackColor = 白色 AlternatingRowStyle-ForeColor = ＃000
< span class =code-attribute> AutoGenerateColumns = false Font-Bo ld = False >
< 列 >
< asp：BoundField DataField = UserName HeaderText = 用户名 / >
< asp：BoundField < span class =code-attribute> DataField = DocumentType HeaderText = 文档类型 / >
< asp：BoundField DataField = FormType HeaderText = 表单类型 / >
< asp：BoundField DataField = 描述 HeaderText = 描述 / >
< asp：TemplateField ItemStyle-HorizontalAlign = 中心 >
< ItemTemplate >
< asp： LinkButton ID = lnkDownload runat = server 文字 = 下载 OnClick = document.getElementById（'light'）。style.display ='block'; document.getElementById（'fade'）。style.display ='block'
< span class =code-attribute> < span class =code-attribute> CommandArgument =' <％ #Eval（ Id）％> ;' > < / asp ：LinkButton >
< / ItemTemplate >
< / asp：TemplateField >
< / Columns >
< / asp：GridView >
文件下载代码
protected void DownloadFile（object sender，EventArgs e）
{
int id = int.Parse（（sender as LinkButton）.CommandArgument）;
byte [] bytes;
string DocumentType，FormType，fileName，Description，contentType;
string constr = ConfigurationManager.ConnectionStrings [constr]。ConnectionString;
using（SqlConnection con = new SqlConnection（constr））
{
using（SqlCommand cmd = new SqlCommand（））
{
cmd.CommandText =从tblFiles中选择UserName，DocumentType，FormType，Name，Data，ContentType，Description;
cmd.Parameters.AddWithValue（@ Id，id）;
cmd.Connection = con;
con.Open（）;
使用（SqlDataReader sdr = cmd.ExecuteReader（））
{
sdr.Read（）;
bytes =（byte []）sdr [Data];
DocumentType = sdr [DocumentType]。ToString（）;
FormType = sdr [FormType ] .ToString（）;
contentType = sdr [ContentType]。ToString（）;
fileName = sdr [Name]。ToString（）;
描述= sdr [描述] .ToString（）;
}
con.Close（）;
}
}
Response.Clear（）;
Response.Buffer = true;
Response.Charset =;
Response.Cache.SetCacheability（HttpCacheability.NoCache）;
回复.ContentType = contentType;
Response.AppendHeader（Content-Disposition，附件; filename =+ fileName）;
Response.BinaryWrite（bytes）;
Response.Flush（）;
Response.End（）;
}
otp提交按钮代码
if（txtOtp.Text == txtName.Text）
{
Response.Write（< script> alert（ '匹配......'）< / script>）;
//这里我想下载文件
}
else
{
Response.Write（< script> alert（'wrong otp .......'）< / script>）;
}
在你的代码中，它是在链接按钮的OnClick属性上触发javascript代码，这是不正确的。你需要使用OnClientClick来激活Javascript函数和OnClick来激活服务器端功能。
第1步：为Gridview添加以下代码
< asp：GridView < span class =code-attribute> ID = GridView1 runat = server HeaderStyle-BackColor = ＃cccccc HeaderStyle-ForeColor = 黑色
RowStyle-BackColor = white RowStyle-ForeColor = ＃003366 AlternatingRowStyle-BackColor = 白色 AlternatingRowStyle-ForeColor = ＃000
AutoGenerateColumns = false 字体粗体 = 错误 >
< 列 >
< asp：BoundField DataField = UserName HeaderText = 用户名 / >
< asp：BoundField DataField = DocumentType HeaderText = 文档类型 / >
< asp：BoundField DataField = FormType HeaderText = 表单类型 / >
< asp：BoundField DataField = 描述 HeaderText = 描述 / >
< asp：TemplateField ItemStyle-HorizontalAlign = 中心 >
< ItemTemplate >
< asp：LinkButton ID = lnkDownload runat = server 文字 = 下载 OnClick = DownloadFile OnClientClick = document.getElementById（'light'）。style.display ='block'; document.getElementById（'fade '）。style.display ='block';
CommandArgument =' <％ #Eval（ Id）％>' > < / asp：LinkButton >
< / ItemTemplate >
< / asp：TemplateField >
< /列 >
< / asp：GridView >
第2步：添加以下代码以解雇服务器端事件。
受保护 void DownloadFile（ object sender，EventArgs e）
{
string filePath =（sender as LinkButton）.CommandArgument;
Response.ContentType = ContentType;
Response.AppendHeader（ Content-Disposition， attachment; filename = + Path.GetFileName（filePath））;
Response.WriteFile（filePath）;
Response.End（）;
}
i have the following gridview with download option(link button) , when i click download am sending otp to mobile,
then am entering otp then submit and download should start
my problem is
when i submit otp download should start,
how can i give link to submit button and grid view linkbutton
aspx code
<asp:GridView ID="GridView1" runat="server" HeaderStyle-BackColor="#cccccc" HeaderStyle-ForeColor="Black"
RowStyle-BackColor="white" RowStyle-ForeColor="#003366" AlternatingRowStyle-BackColor="White" AlternatingRowStyle-ForeColor="#000"
AutoGenerateColumns="false" Font-Bold="False">
<Columns>
<asp:BoundField DataField="UserName" HeaderText="User Name" />
<asp:BoundField DataField="DocumentType" HeaderText="Document Type" />
<asp:BoundField DataField="FormType" HeaderText="Form Type" />
<asp:BoundField DataField="Description" HeaderText="Description" />
<asp:TemplateField ItemStyle-HorizontalAlign="Center">
<ItemTemplate>
<asp:LinkButton ID="lnkDownload" runat="server" Text="Download" OnClick="document.getElementById('light').style.display='block';document.getElementById('fade').style.display='block'"
CommandArgument='<%# Eval("Id") %>'></asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
file download code
protected void DownloadFile(object sender, EventArgs e)
{
int id = int.Parse((sender as LinkButton).CommandArgument);
byte[] bytes;
string DocumentType, FormType, fileName, Description, contentType;
string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
using (SqlConnection con = new SqlConnection(constr))
{
using (SqlCommand cmd = new SqlCommand())
{
cmd.CommandText = "select UserName,DocumentType,FormType,Name, Data, ContentType,Description from tblFiles ";
cmd.Parameters.AddWithValue("@Id", id);
cmd.Connection = con;
con.Open();
using (SqlDataReader sdr = cmd.ExecuteReader())
{
sdr.Read();
bytes = (byte[])sdr["Data"];
DocumentType = sdr["DocumentType"].ToString();
FormType = sdr["FormType"].ToString();
contentType = sdr["ContentType"].ToString();
fileName = sdr["Name"].ToString();
Description = sdr["Description"].ToString();
}
con.Close();
}
}
Response.Clear();
Response.Buffer = true;
Response.Charset = "";
Response.Cache.SetCacheability(HttpCacheability.NoCache);
Response.ContentType = contentType;
Response.AppendHeader("Content-Disposition", "attachment; filename=" + fileName);
Response.BinaryWrite(bytes);
Response.Flush();
Response.End();
}
otp submit button code
if (txtOtp.Text == txtName.Text)
{
Response.Write("<script> alert('matched......')</script>");
//here i want to download file
}
else
{
Response.Write("<script> alert('wrong otp.......')</script>");
}
In your code, it is firing javascript code on "OnClick" property of Link button which is not correct. You need to use OnClientClick to fire Javascript function and OnClick to fire Server side function.
Step 1: Add following code for Gridview
<asp:GridView ID="GridView1" runat="server" HeaderStyle-BackColor="#cccccc" HeaderStyle-ForeColor="Black" RowStyle-BackColor="white" RowStyle-ForeColor="#003366" AlternatingRowStyle-BackColor="White" AlternatingRowStyle-ForeColor="#000" AutoGenerateColumns="false" Font-Bold="False"> <Columns> <asp:BoundField DataField="UserName" HeaderText="User Name" /> <asp:BoundField DataField="DocumentType" HeaderText="Document Type" /> <asp:BoundField DataField="FormType" HeaderText="Form Type" /> <asp:BoundField DataField="Description" HeaderText="Description" /> <asp:TemplateField ItemStyle-HorizontalAlign="Center"> <ItemTemplate> <asp:LinkButton ID="lnkDownload" runat="server" Text="Download" OnClick = "DownloadFile" OnClientClick="document.getElementById('light').style.display='block';document.getElementById('fade').style.display='block';" CommandArgument='<%# Eval("Id") %>'></asp:LinkButton> </ItemTemplate> </asp:TemplateField> </Columns> </asp:GridView>
Step 2: Add following code to fire server side event.
protected void DownloadFile(object sender, EventArgs e) { string filePath = (sender as LinkButton).CommandArgument; Response.ContentType = ContentType; Response.AppendHeader("Content-Disposition", "attachment; filename=" + Path.GetFileName(filePath)); Response.WriteFile(filePath); Response.End(); }
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