如何使用string.h函数在C中用另一个单词替换单词 [英] How do I replace a word with another in C using string.h functions

问题描述

#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main()
{
    char text[100], cuv1[50], cuv2[50], text2[100];
    char sep[] = " '\",.!?";
    int i=0, j=0;
    fgets(text, 100, stdin);
    text[strlen(text) - 1] = '\0';
    fgets(cuv1, 50, stdin);
    cuv1[strlen(cuv1) - 1] = '\0';
    fgets(cuv2, 50, stdin);
    cuv2[strlen(cuv2) - 1] = '\0';
    while(strstr( (text + i) , cuv1))
    {
        int a = strstr( (text + i) , cuv1) - (text + i);
        int b = strstr( (text + i) , cuv1) - (text + i) + strlen(cuv1);
        if( ( (a == 0) || strchr(sep, (text + i)[a - 1]) ) && ( ( (text + i)[b] == '\0') || strchr(sep, (text + i)[b]) ) )
        {
            int x;
            for(x=0; x<a;>{
                text2[j] = (text + i)[x];
                j++;
            }
            i = i + b;
            strcat(text2, cuv2);
            printf("Textul 2 devine: %s\n", text2);
            i = i + strlen(cuv1);
            j = j + strlen(cuv2);
            			
        }
        else
        {
            int x;
            for(x=0; x<b;>{
                text2[j] = (text + i)[x];
                j++;
            }
            i = i + b;
        }
    }
    printf("Textul final este: %s\n", text2);
    return 0;
}

推荐答案

以旧方式提供一种可能的解决方案。

Here one possible solution in old fashion.

/* NOTE: 
You must control de strOut length if not ... 
or you are in trouble 
the allocate space must be there
*/
int
replace( char *strIn, char *sStr, char *rStr, char *strOut)
{
  /* 
   Validate input fields
  PRECONDITION( strIn !=NULL );
  PRECONDITION( strOut!=NULL );
  PRECONDITION( sStr  !=NULL );
  PRECONDITION( rStr  !=NULL );*/
  
  int i=0,j=0;
  int iLen = strlen( strIn);
  int sLen = strlen( sStr );
  int rLen = strlen( rStr );
  
  //Trim trailing and heading spaces (optional)
  //RTrim(sStr,sLen);
  //LTrim(sStr,sLen);
  
  for( i=0; i<iLen; i++) {
    if( strncmp(&strIn[i], sStr, sLen)) strOut[j++]=strIn[i];
	else {
	  memcpy( &strOut[j], rStr, rLen);
	  j+=rLen;
          i+=(sLen-1);
	}
  }
  strOut[j]=0; 
  return EXIT_SUCCESS;
}

int
main(int argc, char *argv[])
{
  char in[]="jjjadhjhas jhasdjhdakdjah jhasdjhas";
  char sStr[]="as";
  char rStr[]="xxxx";
  char out[200];
  int retCode = replace( in, sStr, rStr, out);
  fprintf(stderr, "Input String  : %s\n", in);
  fprintf(stderr, "Search String : %s\n", sStr);
  fprintf(stderr, "Replace String: %s\n", rStr);
  fprintf(stderr, "Result String : %s\n", out);
  fprintf(stderr, "Return Code: %d\n", retCode);  
  exit(EXIT_SUCCESS);
}

就像那样：

Like that:

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <string.h>

void word_replace(char* str, char* word_old, char* word_new)
{
	char* wd_buf = NULL;
	if ((wd_buf = strstr(str, word_old)) != NULL)
	{
		int old_len = strlen(word_old);
		int new_len = strlen(word_new);
		int len = abs(old_len - new_len);
		while (--len >= 0 && old_len < new_len)
		{
			int pos = strlen(str);
			while (--pos >= wd_buf - str)
				str[pos + 1] = str[pos];
		}

		memcpy((void*)&str[wd_buf - str], (const void*)word_new, new_len);

		if (new_len < old_len)
		{
			memcpy((void*)&str[wd_buf - str + new_len],
				(const void*)&str[wd_buf - str + old_len],
                                 strlen(&str[wd_buf - str + old_len]));
		}
	}
}

int main(int argc, char* argv[])
{
	char str[256] = "lazy dog jumps over a brown fox\0";

	char word_old[256] = "dog";
	char word_new[256] = "straus";

	word_replace(str, word_old, word_new);

	printf("%s\n", str);

	_getch();

	return 0;
}

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