c ++ Structures导出特定名称的数据 [英] c++ Structures export data for specific name

问题描述

这就是我创建的结构：





< pre lang =C ++> #include < < span class =code-leadattribute> iostream >
#include < string >
#include < fstream >
使用 命名空间标准;


struct 学生
{
char first_name [ 10 ];
char last_name [ 10 ];
char country [ 20 ];


};
int main（）
{
学生数组 [ 10 ];
int n，i;
cin>> N;

for （i = 0 ; i< n; i ++）
{
cout<< 名称：;
cin>> array [i] .first_name;
cout<< 姓氏：;
cin>> array [i] .last_name;
cout<< 国家/地区：;
cin>> array [i] .country;

}

for （i = 0 ; i< n; i ++）
{
cout<< array [i] .first_name<< ;
cout<< array [i] .last_name<< ;
cout<< array [i] .country<< ;


}
system（ pause ）;


}

我必须编写代码，一旦我进入John（例如）显示有关他的所有信息：姓氏，国家。当我输入国家出口：名字，姓氏。也许我没有正确解释。因为我的英语不好。也许这就是我无法找到具体信息或类似例子的原因。


输出示例：

 n = 2 
姓名：John 
姓：Doe 
国家：England 
 
姓名：Pete 
姓：Donaldson 
国家：美国

这是我不能做的部分：

 /关于学生/ $的信息b $ b输入要检查的名称：
 John 

此处输出必须为：

姓名：John 
姓氏：Doe 
国家：英格兰

另一张支票：

如果我输入Pete：

姓名：Pete 
姓：Donaldson 
国家：美国

我我应该能够无限制地检查。



我试着这样做：

  for （i =  0 ; i< n; i ++）
  char  name_for_check [ 10 ]; 
 cin>> name_for_check; 
  for （i =  0 ; i< n; i ++）
 { 
  if （strcmp（ array  [i] .first_name，name_for_check）==  0 ）
 {
 cout<<  array  [i] .first_name<<  ; 
 cout<<  array  [i] .last_name<<  ; 
 cout<<  array  [i] .country<<  ; 
} 
} 
} 

但是如何这样做我可以为name_for_check发出无限数量的请求。

我的意思是我可以多次检查名称。

解决方案

可能这个，我实际上并不了解问题所在描述：

 做 
 {
  char  name_for_check [ 10 ] =  < span class =code-string> \0; 
 cin>> name_for_check; 
  if （strcmp（  quit，name_for_check）<  0 ）
 {
  bool  found =  false ; 
  for （i =  0 ; i< n&& found == < span class =code-keyword> false ; i ++）
  if （！strcmp（ array  [i] .first_name，name_for_check））
 {
 cout<<  array  [i] .first_name<<  ; 
 cout<<  array  [i] .last_name<<  ; 
 cout<<  array  [i] .country<<  ; 
 found =  true ; 
} 
} 
}  while （！strcmp（ < span class =code-string>退出，name_for_check））; 

以下代码请求用户无限输入，直到输入包含quit的字符串。我认为它应该解决以下问题

That is the structure that I created:

#include <iostream>
#include <string>
#include <fstream>
using namespace std;


struct Students
{
	char first_name[10];
	char last_name[10];
	char country[20];


};
int main()
{
	Students array[10];
	int n, i;
	cin >> n;

	for (i = 0; i < n; i++)
	{
		cout << "Name:";
		cin >> array[i].first_name;
		cout << "Last Name:";
		cin >> array[i].last_name;
		cout << "Country:";
		cin >> array[i].country;

	}

	for (i = 0; i < n; i++)
	{
		cout << array[i].first_name << " ";
		cout << array[i].last_name << " ";
		cout << array[i].country << " ";


	}
	system("pause");


}

And I have to write code that once I enter John (for example) displays all information about him: last name, country. And when I enter country to export: first name, last name. Maybe I don't explain it properly. Because my english is bad. Maybe that's the reason that i can't find specific information or similar examples.

Ouput example:

n=2
Name:John
Last Name: Doe
Country: England

Name:Pete
Last Name: Donaldson
Country: USA

And that's the part that i can't do:

/Info about student/
Enter Name for check:
John

and here the output must be:

Name:John
Last Name: Doe
Country: England

another check:
if I enter Pete:

Name:Pete
Last Name: Donaldson
Country: USA

I should be able to make unlimited checks.

I tryed to make it like this:

for (i = 0; i < n; i++)
char name_for_check[10];
cin >> name_for_check;
for (i = 0; i < n; i++)
{
	if (strcmp(array[i].first_name, name_for_check) == 0)
	{
		cout << array[i].first_name << " ";
		cout << array[i].last_name << " ";
		cout << array[i].country << " ";
	}
}
}

But how to do so that I can make an unlimited number of requests for name_for_check.
I mean that i can check name more than one time.

解决方案

Probably this one, I don't actually understand the condition of the problem being described:

do
{
     char name_for_check[10] = "\0";
     cin >> name_for_check;
     if (strcmp("quit", name_for_check) < 0)
     {
         bool found = false;
         for (i = 0; i < n && found == false; i++)
    	      if (!strcmp(array[i].first_name, name_for_check))
              { 	
		  cout << array[i].first_name << " ";
		  cout << array[i].last_name << " ";
		  cout << array[i].country << " ";
                  found = true;
  	      }
     }
}while(!strcmp("quit", name_for_check));

The following code requsts for a user input infinitely until the string containing "quit" is typed in. I think that it should solve the following problem

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