如何在C ++中使用静态转换技术更改此代码（以下代码正常工作） [英] How Do I Change This Code By Using Static Cast Technique In C++(Below Code Works Properly)

问题描述

for（int i = 0; i< 128; i ++）

{

string str =;

char chr = i;

stringstream chartostr;

chartostr<< CHR;

chartostr>> str;

}

i希望将char转换为字符串，上面的代码是正确的工作，但有没有专门的方法来做到这一点？

for(int i=0; i<128; i++)
{
string str = "";
char chr = i;
stringstream chartostr;
chartostr << chr;
chartostr >> str;
}
i want to convert char to string, above code is work corretly, but is there a pro way to do this ?

推荐答案

我会替换

I would replace

Quote：

string str =;

char chr = i;

stringstream chartostr;

chartostr<< CHR;

chartostr>> str;

string str = "";
char chr = i;
stringstream chartostr;
chartostr << chr;
chartostr >> str;

with

with

string str;
str += static_cast<char>(i);
</char>

我不明白的目的循环。你想做什么？

用 str 声明在里面<$ c $的主体c> for 循环，当循环退出时，你没有任何东西可以显示它！这样的东西不会得到你想要的东西吗？

With str declared inside the body of your for loop, when the loop exits you have nothing to show for it! Wouldn't something like this get you what you want?

string Ascii7(128, '\0');
for (int i = 1; i < 128; ++i)
{
  Ascii7[i] = static_cast<char>(i);
}

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