c＃ - 从随机数中取出另一个数字的百分比 [英] c# - making a percent from a random number out of another number

问题描述

好吧所以这是一个游戏命令，它运作完美，但我无法弄清楚如何使十进制pc = num * rand / 100，因为兰德并没有真正定义一个数字。

 内部  class  GambleCommand：命令
 {
  public  GambleCommand（）
： base （  roll， 3 ）
 {
} 
 
  protected   override   bool 进程（播放器播放器，RealmTime时间，字符串 [] args）
 {
 尝试 
 {
  if （args.Length ==  1 ）
 {
  int  num =  int  .Parse（args [ 0 ]）; 
 Random rnd =  new  Random（）; 
  string  pl = player.Name; 
  string  rand =  ; 
  if （num <   0 ）rand = rnd.Next（num， 0 ）。ToString（）; 
  else  rand = rnd.Next（ 0 ，num）.ToString（）; 
  decimal  pc = num * rand /  100 ; 
  foreach （客户i   player.Manager.Clients.Values）
 { 
 i.SendPacket（ new  TextPacket 
 {
 BubbleTime =  0  ，
 Stars = -1，
 Name = pl，
 Text =   roll  + rand +   out of + num +  。（ + pc +  ％） 
}）; 
} 
} 
} 
 
  catch  
 {
 Random rnd =  new  Random（）; 
  string  pl = player.Name; 
  string  rand = rnd.Next（ 0 ， 100 ）的ToString（）; 
  foreach （客户i   player.Manager.Clients.Values）
 { 
 i.SendPacket（ new  TextPacket 
 {
 BubbleTime =  0  ，
 Stars = -1，
 Name = pl，
 Text =   roll a + rand +  满分100分。 
}）; 
} 
} 
 返回  true ; 
} 
} 
 

除了那个命令基本上从0-中选出一个数字之外别无其他解释num（num是您选择的数字）。我想要它，以便它在游戏中说出它的百分比。请尽快帮助！

解决方案

首先，您应该尝试使用整数

  int  rand; 
 ... 
 rand = rnd.Next（num， 0 ）; 

并更改公式

  int  pc = rand *  100  / NUM; 

应该更好！

也许尝试小数。 Parse或decimal.TryParse，如果你想继续进行字符串转换。

  decimal  pc = num *  decimal  .Parse（rand）/  100 ; 

好吧我修好了所以我不得不把它更改为

  decimal  pc =  decimal  .Parse（rand）/ num *  100 ; 

Alright so this is an in game command and it works perfect but I just can't figure out how to make decimal pc = num * rand / 100 because rand doesn't really define one number.

        internal class GambleCommand : Command
{
    public GambleCommand()
        : base("roll", 3)
    {
    }

    protected override bool Process(Player player, RealmTime time, string[] args)
    {
        try
        {
            if (args.Length == 1)
            {
                int num = int.Parse(args[0]);
                Random rnd = new Random();
                string pl = player.Name;
                string rand = "";
                if (num < 0) rand = rnd.Next(num, 0).ToString();
                else rand = rnd.Next(0, num).ToString();
                decimal pc = num * rand / 100;
                foreach (Client i in player.Manager.Clients.Values)
                    {
                    i.SendPacket(new TextPacket
                    {
                        BubbleTime = 0,
                        Stars = -1,
                        Name = pl,
                        Text = "rolled a " + rand + " out of " + num + ". (" + pc + "%)"
                        });
                    }
                }
            }

        catch
        {
            Random rnd = new Random();
            string pl = player.Name;
            string rand = rnd.Next(0, 100).ToString();
            foreach (Client i in player.Manager.Clients.Values)
            {
                i.SendPacket(new TextPacket
                {
                    BubbleTime = 0,
                    Stars = -1,
                    Name = pl,
                    Text = "rolled a " + rand + " out of 100."
                });
            }
        }
        return true;
    }
}

There isn't to much to explain other then that the command basically picks a number out of 0-num (num is a number that you choose). I want it so that it gives the percent when it says it in game. Please help asap!

解决方案

First, you should try with integer

int rand;
...
rand = rnd.Next(num, 0);

And change the formula

int pc = rand * 100 / NUM;

Should be better !

Maybe try decimal.Parse or decimal.TryParse, if you want to continue on the road of string conversions.

decimal pc = num * decimal.Parse(rand) / 100;

Alright I fixed it so I had to change it to

decimal pc = decimal.Parse(rand) / num * 100;

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