如何从AT命令解析PDU字符串？ [英] How to Parse PDU String from AT Commands?

问题描述

您好，您能否分享一下如何获取特定字符串的代码？

这是整个字符串。

 AT + CMGL = 4\r\r\\\
 + CMGL：1,2，...，48\r\\\
079136190800101011000BA19084537777F70008AA2200540065007300740020004D0065007300730061006700650020005000440055002E\r\\\
 + CMGL：2,1，，34\r\\\
0791361908005043040C9136493875777700005101519103652311D4F29C0E6A96E7F3F0B90C8212AB2E \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ b'预郎= 文本> 079136190800101011000BA19084537777F70008AA2200540065007300740020004D0065007300730061006700650020005000440055002E 

或

<预郎= 文本> 0791361908005043040C9136493875777700005101519103652311D4F29C0E6A96E7F3F0B90C8212AB2E

这是我用过但不起作用的代码。

  public  ShortMessageCollection ParseMessagesPDU（ string  input）
 {
 ShortMessageCollection messages =  new  ShortMessageCollection（）; 
 
 尝试 
 {
 Regex r =  new 正则表达式（ @  \ + CMGL：（\d +），（\d +）,,（\d + ）\\\\\（。*？）\\\\\\ n，RegexOptions.IgnoreCase | RegexOptions.Singleline）; 
 
匹配m = r.Match（输入）; 
  while （m.Success）
 {
 ShortMessage msg =  new  ShortMessage（）; 
  //   msg.Index = int.Parse（m.Groups [1] .Value）;  
 msg.Index = m.Groups [ 1 ]。值; 
 msg.Status = m.Groups [ 2 ]。价值; 
 msg.Sender = m.Groups [ 3 ]。值; 
 msg.Alphabet = m.Groups [ 4 ]。价值; 
 msg.Sent = m.Groups [ 5 ]。值; 
 msg.Message = m.Groups [ 6 ]。值; 
 messages.Add（msg）; 
 
 m = m.NextMatch（）; 
} 
} 
  catch （例外情况）
 {
  //   throw ex;  
} 
  return 条消息; 
} 

希望你能解决这个问题。



谢谢。

解决方案

用一个 <替换双 \ code> \ 。您使用的是C＃逐字字符串（ @...），因此，每个字符都按原样使用 - 不需要转义（除外） 必须加倍才能进行转义。另请参阅在C＃中转义：字符，字符串，字符串格式，关键字，标识符 [ ^ ]。

干杯

Andi

< blockquote>如果你想要的只是长六角形字符串，这个正则表达式应该有效。

 \\\\\\ n [0-9A-F] + \\\\\\ n 

或

 \\ \\\\ [0-9A-F] {10，} \\\\\\ //至少10个字符

您也可以跳过\\\\ n。

Hello, can you share my the code on how to get only the certain string?
this is the whole string.

AT+CMGL=4\r\r\n+CMGL: 1,2,,48\r\n079136190800101011000BA19084537777F70008AA2200540065007300740020004D0065007300730061006700650020005000440055002E\r\n+CMGL: 2,1,,34\r\n0791361908005043040C9136493875777700005101519103652311D4F29C0E6A96E7F3F0B90C8212AB2E\r\n\r\nOK\r\n

now I wan to parse and get only this.

079136190800101011000BA19084537777F70008AA2200540065007300740020004D0065007300730061006700650020005000440055002E

or

0791361908005043040C9136493875777700005101519103652311D4F29C0E6A96E7F3F0B90C8212AB2E

this is the code that I've used but not working.

public ShortMessageCollection ParseMessagesPDU(string input)
{
    ShortMessageCollection messages = new ShortMessageCollection();

    try
    {
        Regex r = new Regex(@"\+CMGL: (\d+),(\d+),,(\d+)\\r\\n(.*?)\\r\\n", RegexOptions.IgnoreCase | RegexOptions.Singleline);

        Match m = r.Match(input);
        while (m.Success)
        {
            ShortMessage msg = new ShortMessage();
            //msg.Index = int.Parse(m.Groups[1].Value);
            msg.Index = m.Groups[1].Value;
            msg.Status = m.Groups[2].Value;
            msg.Sender = m.Groups[3].Value;
            msg.Alphabet = m.Groups[4].Value;
            msg.Sent = m.Groups[5].Value;
            msg.Message = m.Groups[6].Value;
            messages.Add(msg);

            m = m.NextMatch();
        }
    }
    catch (Exception ex)
    {
        //throw ex;
    }
    return messages;
}

Hope you can help me with this problem.

Thank you.

解决方案

Replace the double \ by one \. You are in a C# verbatim string (@"..."), so, each character is taken as is - no escaping needed (except for " which must be doubled for escaping). See also Escaping in C#: characters, strings, string formats, keywords, identifiers[^].
Cheers
Andi

This regex should work if the only thing you want is the long hex-string.

\\r\\n[0-9A-F]+\\r\\n

or

\\r\\n[0-9A-F]{10,}\\r\\n  //At least 10 characters

You can probably skip the \r\n as well.

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