无效的间接运算符 [英] invalid indirection operator

问题描述

我想显示每个销售人员的总销售额，工资，并确定以下类别中的工资收入



$ 100- $ 500

$ 501-900 $

$ 900以上。



每个销售人员（有10个）收到100美元加上他的总sasles的10％

I wanted to display the gross sales, salary of each salesperson and determine how many earned salaries in the following categories

$100-$500
$501-900$
$900-above.

Each salesperson(there are 10) receives $100 plus 10% of his gross sasles

#include<iostream.h>
#include<stdio.h>
#include<conio.h>
int main(){
    clrscr();
    int gross_sale[10],i,salary ;
    int ctr1=0,ctr2=0,ctr3=0,r1=5,r2=5,r3=5;
    printf("ENTER GROSS SALES\n");
    
    for(i=0;i<10;i+1){
        printf("Salesperson %d: ",i++);
        scanf("%d",gross_sale[i]);
    
    }
    
    
    clrscr();
    salary=100+gross_sale[i]/10;
    for(i=0;i<10;i++){
    if (salary<500 && salary>100)
    {
        gotoxy(10,r1); printf("Salesperson %d : %d",i+1, salary);
        r1++;ctr1++;
    }
    else if (salary >= 501 && salary <=900){
        gotoxy(35,r2); printf("Salesperson %d : %d",i+1,salary);
        r3++;ctr3++;
    }
    else
    {
        gotoxy(60,r3); printf("Salesperson%d: %d",i+1,salary);
        r3++;ctr3++;
    }
    
    
    printf("\n\n\n");
    printf("Salesperson who earned salaray from $900-and better %d\n",ctr1);
    printf("Salesperson who earned salaray from $500-$900 %d\n",ctr2);
    printf("Salesperson who earned salaray from $100-$500 %d\n",ctr3);
    
    gotoxy(24,1);
    printf("SALARY CATEGORIES\n");
    printf("\n[$100-$500]\t\t[$501-$900]\t\t[$901 and better]");
    
    
    getch();
    return 0;
    }
}
</conio.h></stdio.h></iostream.h>

推荐答案

100 -

500

500

501-900

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