以下程序的输出是什么？这里％dn在printf中的作用是什么。 [英] What is the output of following Program ? Here what is the role of %dn inside printf .

问题描述

#include <stdio.h>

void main()
{
        int a = 100;
        int b = 3;
        int c;

        c = a + b;
        printf( "a + b = %dn", c );

        c = a - b;
        printf( "a - b = %dn", c );

        /* multiplication performed before call to printf() */
        printf( "a * b = %dn", a * b );

        c = a / b;
        printf( "a / b = %dn", c );

        c = 100 % 3;
        printf( "a % b = %dn", c );
}

推荐答案

％d表示输出为 d igit（有符号十进制整数） ）： http://www.cplusplus.com/reference/cstdio/printf/ [ ^ ]

你在 \ n，试试这个：

%d means that the output is a digit (Signed decimal integer): http://www.cplusplus.com/reference/cstdio/printf/[^]
You are missing backslash in "\n", try this:

#include <stdio.h>

void main()
{
        int a = 100;
        int b = 3;
        int c;

        c = a + b;
        printf( "a + b = %d\n", c );

        c = a - b;
        printf( "a - b = %d\n", c );

        /* multiplication performed before call to printf() */
        printf( "a * b = %d\n", a * b );

        c = a / b;
        printf( "a / b = %d\n", c );

        c = 100 % 3;
        printf( "a % b = %d\n", c );
}

Umm，％d 用于格式化字符串。但是这里 n 和％d一起使用，这意味着缺少了一些东西，即 \ 或 n 本身如果你想在变量值后打印 n 。



简而言之，它表示一个十进制数后跟一个字符 n 。



-KR

Umm, %d is used to format the string. But here n is used along with the %d, which means there's something missing i.e. \ or n itself if you want to print n after the variable value.

So in short, it signifies a decimal number followed by a character n.

-KR

运行它并查看。



但我怀疑n部分应该是\ n换一个换行。



为什么要求我们为你运行一个程序？这很简单：将其粘贴到IDE中，构建应用程序并运行它！

Run it and see.

But I suspect that the "n" part should be "\n" for a new line instead.

Why ask us to run a program for you? This is trivial: paste it into your IDE, build the app, and run it!

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