如果日期时间选择器中的时间是eqaul到datetime.now，我该如何开始操作？ [英] How can I start an action if the time in the datetime picker is eqaul to datetime.now?

问题描述

嘿伙计们，我是这个论坛的新手，这是我的第一篇文章。我来自德国，差不多17岁。



我的问题有点广泛。

我有一个正常的WindowsFormsApplication。

有7个DateTimePickers，用户可以设置7个不同的时间（hh：mm：ss）。

在程序的底部，有一个应该显示的标签实际时间与7个用户定义时间之一的最小差异。

如果差异等于00:00:00，程序应该显示一个MessageBox，带有差异的标签应该从00更新：00：00到新的差异，实际时间与用户定义的6个时间之一之间的第二个最小差异。

我一周7天都需要这个功能。





我希望，你理解。如果您有任何问题或建议的解决方案，请写信给我。



感谢您的努力。

解决方案

我试图测试每个DateTimePicker。但我想只显示标签中的较小差异。所以我在计时器中写了很多if-querys来显示最小的差异。

如何编写7个DateTimePickers的if-querys？



不要！ ：笑：方式，方式太多组合。

所以...设置一个TimeSpan值数组，并加载7 DateTimePicker值减去当前dateTime：

 DateTime now = DateTime.Now; 
 Timespan [] diffs =  new  TimeSpan [ 7 ]; 
 diffs [ 0 ] = dateTimePicker1.Value  -  now; 
 diffs [ 1 ] = dateTimePicker2.Value  -  now; 
 diffs [ 2 ] = dateTimePicker3.Value  -  now; 
 diffs [ 3 ] = dateTimePicker4.Value  -  now; 
 diffs [ 4 ] = dateTimePicker5.Value  -  now; 
 diffs [ 5 ] = dateTimePicker6.Value  -  now; 
 diffs [ 6 ] = dateTimePicker7.Value  -  now; 

然后使用Array.Sort和你可以轻松获得最大和最小值。

 Array.Sort（diffs）; 
 Timespan min = diffs [ 0 ]; 
 Timespan max = diffs [ 6 ]; 

（显然，我不会在现实世界中使用魔术数字）



并且只能在一个方法中读取一次：它在你的控制之外变化，所以即使这样做：

DateTime now1 = DateTime 。现在;

DateTime now2 = DateTime.Now;

  if （ now1！= now2） throw   new  ApplicationException（ 时间改变了！）; 

有时候，你会得到一个例外，有时你不会......而且他们可以看起来非常不同 - 如果你在错误的时间做这个千禧年！ ：笑：

Hey guys, I'm new in this forum and this is my first post. I come from Germany and I'm almost 17 years old.

My problem is a little extensive.
I hava a normal WindowsFormsApplication.
There are 7 DateTimePickers where the user can set 7 different times (hh:mm:ss).
At the bottom of my program, there is a Label which should show the smallest difference between the actual time and one of the 7 user defined times.
If the difference equals 00:00:00 the program should show me a MessageBox and the label with the difference should update from 00:00:00 to the new difference with the 2nd smallest difference between the actual time and one of the 6 left user defined times.
This function I need for all 7 days of the week.


I hope, you understood. If you have any questions or a suggested solution, please write me.

Thanks for efforts.

解决方案

"I tried to test for every DateTimePicker. But I want to show only the smalles difference in the label. So I wrote a lot of if-querys in a timer to show only the smallest difference.
How can I write the if-querys for 7 DateTimePickers?"

Don't! :laugh: way, way too many combinations.
So...set up an array of TimeSpan values, and load it with the 7 DateTimePicker values minus the current dateTime:

DateTime now = DateTime.Now;
Timespan[] diffs = new TimeSpan[7];
diffs[0] = dateTimePicker1.Value - now;
diffs[1] = dateTimePicker2.Value - now;
diffs[2] = dateTimePicker3.Value - now;
diffs[3] = dateTimePicker4.Value - now;
diffs[4] = dateTimePicker5.Value - now;
diffs[5] = dateTimePicker6.Value - now;
diffs[6] = dateTimePicker7.Value - now;

Then use Array.Sort and you have the maximum and minimum easily available.

Array.Sort(diffs);
Timespan min = diffs[0];
Timespan max = diffs[6];

(Obviously, I wouldn't use "magic numbers" in the real world)

And only ever read the time once in a method: it changes outside your control, so even doing this:
DateTime now1 = DateTime.Now;
DateTime now2 = DateTime.Now;

if (now1 != now2) throw new ApplicationException("The time changed!");

Sometimes, you will get an exception, and sometimes you won't...and they can seem very different - different millenium if you do it at the wrong time! :laugh:

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