无法解决项目欧拉问题6 [英] Can't Solve Project Euler Problem 6

问题描述

您好。



我正在尝试解决项目euler网站上的问题6，但我遇到了麻烦。



这是我到目前为止的代码：

  var  square =  0 ; 
  var  sum =  0 ; 
  var  result =  0 ; 
 
  for （ var  i =  0 ; i<  101 ; i ++）{
 square = 数学 .pow（i， 2 ）; 
 square + = square; 
 
 sum + = i; 
} 
 
 result = 数学 .pow（总和， 2  ） - 方形; 
  console  .log（result）; 

我看到它，for循环开始计数并增加i，变量square首先获取i的幂，然后将其添加到自身。它一次又一次地这样做，所以最终结果应该是从1到100的所有数字到2的幂。之后变量sum计算从1到100的所有数字并将它们存储在自身中。之后，变量result将sum取为2的幂，并从square中取sum。这看起来很符合我的想法，但显然有些错误，因为我得到了错误的结果（25482500）。



有人可以向我解释我做错了什么吗？ div class =h2_lin>解决方案

嗯...看看你的代码：

  for （ var  i =  0 ; i <   101 ; i ++）{
 square = Math.pow（i， 2 < /跨度>）; 
 square + = square; 
 
 sum + = i; 
} 

循环后 square 的值是多少？

答案：20,000

为什么？

因为它只使用最终值绕循环：100 - 所有其他值在下一次循环循环时被丢弃。

和100 * 100 * 2 == 20,000



您需要开始使用调试器来处理这类事情，而不是要求其他人！

Hello.

I'm trying to solve problem 6 at the project euler site, but I'm having trouble.

This is my code so far:

var square = 0;
var sum = 0;
var result = 0;

for (var i = 0; i < 101; i++){
    square = Math.pow(i, 2);
    square += square;
    
    sum += i;
}

result = Math.pow(sum, 2) - square;
console.log(result);

As I see it, the for loop starts counting and increasing i, the variable "square" first takes the power of i and then adds it to itself. It does that again and again so the final result should be all the numbers from 1 to 100 each to the power of 2. After that the variable "sum" counts all the numbers from 1 to 100 and stores them in itself. After that, the variable "result" takes "sum" to the power of 2 and substracts "sum" from "square". This seems pretty logical in my head, but apparently something's wrong as I get the wrong result (25482500).

Can someone please explain to me what I did wrong?

解决方案

Um...Look at your code:

for (var i = 0; i < 101; i++){
    square = Math.pow(i, 2);
    square += square;

    sum += i;
}

What value is in square after the loop?
Answer: 20,000
Why?
Because it only ever uses the final value to go round the loop: 100 - all other values are discarded the next time it goes round the loop.
And 100 * 100 * 2 == 20,000

You need to start using the debugger to work this kind of thing out, rather that asking other people!

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