Treeview节点在单击文本时不扩展 [英] Treeview node not expanding on clicking on text

问题描述

我有一个树视图，其中有两个父节点0的子节点和一个没有ID的主节点。





根节点

0 - >儿童1

1 - > SubChilds

3 ---> SubChild1

1 - >子孙女

0 - >儿童2

2 - > SubChilds

2 - > SubChilds



树结构如上。问题是每当我点击Child 2时，Child 1节点都会被扩展，我已经检查过使用断点并发现每当我点击Child 2时，sleectednode.text会显示Child 1.如何清除它？



下面给出了一段代码：



------------- -----------------------------------

 Treeview1_SelectedNodeChanged（）
 {
 Datatable dt =  //   Treeview绑定 
 ds.tables。 add （dt）; 
 TreeNode selectedNode = New TreeNode（）; 
 selectedNode =  this  .Treeview1.SelectedNode.Text; 
} 

------------------------------ ------------------



这里selectedNode总是显示第一个Child节点的文本，即使我点击第二个子节点。我使用数据表绑定SQL表中的树。





感谢&问候，

SaJ

解决方案

这是因为您的treenodes有重复值，更改行

 parentTreeNode.Value = firstDataRows [ParentId]。ToString（）; 

到

 parentTreeNode.Value = firstDataRows [Id]。ToString（）; 

这样他们就会有独特的价值

Hi,

I have a tree view in which there are two child nodes with parentID 0 and a main node with no ID.


Root Node
0--> Child 1
1--> SubChilds
3--->SubChild1
1--> Subchilds
0--> Child 2
2--> SubChilds
2--> SubChilds

The tree structure is as above. The problem is that whenever I click on Child 2 the Child 1 node gets expanded, I have checked using breakpoints and found out that whenever I click on Child 2 the sleectednode.text shows Child 1. How can I clear this?

A piece of the code is given below :

------------------------------------------------

Treeview1_SelectedNodeChanged()
{
Datatable dt = //Treeview binding
ds.tables.add(dt);
TreeNode selectedNode = New TreeNode();
selectedNode = this.Treeview1.SelectedNode.Text;
}

------------------------------------------------

Here selectedNode always shows the text of the first Child node even if I click on the second Child Node. I am binding the tree from the SQL table using a datatable.


Thank & Regards,
SaJ

解决方案

This happens because your treenodes have duplicate values, change the line

parentTreeNode.Value = firstDataRows["ParentId"].ToString();

to

parentTreeNode.Value = firstDataRows["Id"].ToString();

So that they will have unique values

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