如何将值存储到结果数组中？ [英] How do I store value into a result array?

问题描述

我有4个阵列。 a = 6个索引，b = 20个索引，x& t = 10001个索引。我必须计算10001个值，然后求它，然后将它们全部加起来。我必须使用（a，b）的唯一组合（x，t）的每个值来操作公式。

I have 4 arrays. a=6 indexes, b=20 indexes, x&t=10001 indexes. I have to calculate 10001 values and then sum it and then sum it all up. I have to operate the formula using unique combinations of (a,b) against every value of (x,t).

long double temps[10001];
    long double result = 0;
    long double resids[120];
    for (int i = 0; i < 6; i++)
    {
        for (int j = 0; j < 20; j++)
        {
            for (int k = 0; k < 10001; k++)
            {
                temps[i] = pow((x[k] - (a[i] + (0.955 - a[i])*(exp(-(b[j]) * t[k])))), 2);
                result += temps[i];
            }
            for (int l = 0; l < 120; l++)
            {
                resids[l] = result;
            }
        }
    }

推荐答案

我发现此代码存在多个问题。要专门回答你关于结果数组的问题...

I see multiple problems with this code. To specifically answer your question about the result array ...

long double temps[10001];
long double result = 0;
long double resids[120];
for (int i = 0; i < 6; i++)
{
    for (int j = 0; j < 20; j++)
    {
        result = 0; // unsure
        for (int k = 0; k < 10001; k++)
        {
            temps[i] = pow((x[k] - (a[i] + (0.955 - a[i])*(exp(-(b[j]) * t[k])))), 2);
            result += temps[i];
        }
        resids[i * 20 + j] = result; // <-- 120 results go here.
    }
}

我无法确定在每次i传递开始时是否应将结果重置为零或每个j通过。

I can't tell whether "result" should be reset to zero at the start of each "i" pass or each "j" pass.

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