查找两个英国邮政编码之间的距离 [英] Find Distance between two uk postcodes

问题描述

我使用了以下代码，但http://maps.google.com/maps/geo?q={0}&output=xml始终返回null。还有其他办法吗？

使用System; 
 02.使用System.Net; 
 03.using System.Web; 
 04.使用System.Xml; 
 05. 
 06.namespace Codebrain 
 07. {
 08. public static class Distance 
 09. {
 10. // Long的Handy结构/ lat信息
 11. public struct Coords 
 12. {
 13.公共双倍经度; 
 14.公共双倍纬度; 
 15.} 
 16. 
 17. //单位计算
 18.公共枚举单位
 19. {
 20.里程，
 21.公里
 22.} 
 23. 
 24. //如果Google API无法找到任何邮政编码，或者国家/地区约束失败，则返回null 
 25.公共静态加倍？ BetweenTwoPostCodes（string postcodeA，string postcodeB，string countryCodeWithin，Units units）
 26. {
 27. var ll1 = PostCodeToLongLat（postcodeA，countryCodeWithin）; 
 28. if（！ll1.HasValue）返回null; 
 29. var ll2 = PostCodeToLongLat（postcodeB，countryCodeWithin）; 
 30. if（！ll2.HasValue）返回null; 
 31. return ll1.Value.DistanceTo（ll2.Value，units）; 
 32.} 
 33. 
 34. //英国邮政编码超载
 35.公共静态加倍？ BetweenTwoUKPostCodes（string postcodeA，string postcodeB）
 36. {
 37. return BetweenTwoPostCodes（postcodeA，postcodeB，GB，Units.Miles）; 
 38.} 
 39. 
 40. //使用Google API解析邮政编码（在指定国家/地区内）
 41. public static Coords？ PostCodeToLongLat（string postcode，string countryCodeWithin）
 42. {
 43. //从Google下载XML响应
 44. var client = new WebClient（）; 
 45. var encodedPostCode = HttpUtility.UrlEncode（postcode）; 
 46. var url = string.Format（http://maps.google.com/maps/geo?q={0}&output=xml，encodedPostCode）; 
 47. var xml = client.DownloadString（url）; 
 48. var doc = new XmlDocument（）; 
 49. doc.LoadXml（xml）; 
 50. 
 51. //创建自定义命名空间管理器
 52. var nsmgr = new XmlNamespaceManager（doc.NameTable）; 
 53. nsmgr.AddNamespace（ge，http://earth.google.com/kml/2.0）; 
 54. nsmgr.AddNamespace（oa，urn：oasis：names：tc：ciq：xsdschema：xAL：2.0）; 
 55. 
 56. //有什么结果吗？ 
 57. var nodelist = doc.SelectNodes（// ge：kml / ge：Response / ge：Placemark，nsmgr）; 
 58. if（nodelist == null || nodelist.Count == 0）返回null; 
 59. 
 60. //结果已按准确性排序，因此请先取一个
 61. var node = nodelist [0]; 
 62. 
 63. //检查国家约束
 64. var countryname = node.SelectSingleNode（oa：AddressDetails / oa：Country / oa：CountryNameCode，nsmgr）; 
 65. if（countryname.FirstChild.Value！= countryCodeWithin）
 66. return null; 
 67. 
 68. //获取原始的长/纬坐标（我希望有一个更好的方式.. 
 69. //也许是LeL封闭盒的平均值？）
 70. var coords = node.SelectSingleNode（ge：Point / ge：coordinates，nsmgr）.FirstChild.Value.Split（'，'）; 
 71.双倍经度; 
 72.双倍数; 
 73. if（！Double.TryParse（coords [0]，经度））返回null; 
 74. if（！Double.TryParse（coords [1]，out lattitude））返回null; 
 75. 
 76.返回新Coords 
 77. {
 78.经度=经度，
 79.纬度= beitude 
 80.}; 
 81.} 
 82. 
 83. public static double DistanceTo（此Coords from，Coords to，Units units）
 85. {
 85. // Haversine公式... 
 86. var dLat1InRad = from.Latitude *（Math.PI / 180.0）; 
 87. var dLong1InRad = from.Longitude *（Math.PI / 180.0）; 
 88. var dLat2InRad = to.Latitude *（Math.PI / 180.0）; 
 89. var dLong2InRad = to.Longitude *（Math.PI / 180.0）; 
 90. 
 91. var dLongitude = dLong2InRad  -  dLong1InRad; 
 92. var dLatitude = dLat2InRad  -  dLat1InRad; 
 93. 
 94. //中间结果a。 
 95. var a = Math.Pow（Math.Sin（dLatitude / 2.0），2.0）+ 
 96. Math.Cos（dLat1InRad）* Math.Cos（dLat2InRad）* 
 97 .Math.Pow（Math.Sin（dLongitude / 2.0），2.0）; 
 98. 
 99. //中间结果c（弧度中的大圆距离）。 
 100. var c = 2.0 * Math.Atan2（Math.Sqrt（a），Math.Sqrt（1.0  -  a））; 
 101. 
 102. //计量单位
 103. var radius = 6371; 
 104. if（units == Units.Miles）radius = 3959; 
 105. 
 106. return radius * c; 
 107.} 
 108.} 
 109.} 
 / xml> 

解决方案

< blockquote>如果您在浏览器中加载XML，您将看到以下错误消息：

地理编码API v2已被在2013年9月9日拒绝了。现在应该使用Geocoding API v3。有关详情，请访问 https://developers.google.com/maps/documentation/geocoding/ [ ^ ]

如果您点击该链接，您会看到一个页面，其中包含有关升级到v3的详细信息：

https://developers.google.com/maps/articles/geocodingupgrade [ ^ ]



如果您仔细阅读，您会发现需要使用新端点：

https://maps.googleapis.com/maps/api/geocode/xml?address={0}

你必须使用Google Maps&放置API以获得两个地方之间的距离。请查看以下链接，了解如何：



http://www.aspsnippets.com/Articles/Google-Maps-V3-Calculate-Distance-Travel-持续时间 - 绘制 - 绘图 - 路线 - 和 - 显示 - 两个位置之间的方向.aspx [ ^ ]

I have used the following code, but http://maps.google.com/maps/geo?q={0}&output=xml, always returns null. Is there any other way to do it?

using System;  
02.using System.Net;  
03.using System.Web;  
04.using System.Xml;  
05.  
06.namespace Codebrain  
07.{  
08.    public static class Distance  
09.    {  
10.        // Handy structure for Long/Lat information  
11.        public struct Coords  
12.        {  
13.            public double Longitude;  
14.            public double Latitude;  
15.        }  
16.  
17.        // Unit calculations  
18.        public enum Units  
19.        {  
20.            Miles,  
21.            Kilometres  
22.        }  
23.  
24.        // Will return a null if the Google API is unable to find either post code, or the country constraint fails  
25.        public static double? BetweenTwoPostCodes(string postcodeA, string postcodeB, string countryCodeWithin, Units units)  
26.        {  
27.            var ll1 = PostCodeToLongLat(postcodeA, countryCodeWithin);  
28.            if (!ll1.HasValue) return null;  
29.            var ll2 = PostCodeToLongLat(postcodeB, countryCodeWithin);  
30.            if (!ll2.HasValue) return null;  
31.            return ll1.Value.DistanceTo(ll2.Value, units);  
32.        }  
33.  
34.        // Overload for UK post codes  
35.        public static double? BetweenTwoUKPostCodes(string postcodeA, string postcodeB)  
36.        {  
37.            return BetweenTwoPostCodes(postcodeA, postcodeB, "GB", Units.Miles);  
38.        }  
39.  
40.        // Uses the Google API to resolve a post code (within the specified country)  
41.        public static Coords? PostCodeToLongLat(string postcode, string countryCodeWithin)  
42.        {  
43.            // Download the XML response from Google  
44.            var client = new WebClient();  
45.            var encodedPostCode = HttpUtility.UrlEncode(postcode);  
46.            var url = string.Format("http://maps.google.com/maps/geo?q={0}&output=xml", encodedPostCode);  
47.            var xml = client.DownloadString(url);  
48.            var doc = new XmlDocument();  
49.            doc.LoadXml(xml);  
50.  
51.            // Create a custom namespace manager  
52.            var nsmgr = new XmlNamespaceManager(doc.NameTable);  
53.            nsmgr.AddNamespace("ge", "http://earth.google.com/kml/2.0");  
54.            nsmgr.AddNamespace("oa", "urn:oasis:names:tc:ciq:xsdschema:xAL:2.0");  
55.  
56.            // Any results?  
57.            var nodelist = doc.SelectNodes("//ge:kml/ge:Response/ge:Placemark", nsmgr);  
58.            if (nodelist == null || nodelist.Count == 0) return null;  
59.  
60.            // Results are already ordered by accuracy, so take the first one  
61.            var node = nodelist[0];  
62.  
63.            // Check the Country constraint  
64.            var countryname = node.SelectSingleNode("oa:AddressDetails/oa:Country/oa:CountryNameCode", nsmgr);  
65.            if (countryname.FirstChild.Value != countryCodeWithin)  
66.                return null;  
67.  
68.            // Get the raw Long/Lat coordinates (I wish there was a nicer way..  
69.            // perhaps averaging the LongLat enclosing box?)  
70.            var coords = node.SelectSingleNode("ge:Point/ge:coordinates", nsmgr).FirstChild.Value.Split(',');  
71.            double longitude;  
72.            double lattitude;  
73.            if (!Double.TryParse(coords[0], out longitude)) return null;  
74.            if (!Double.TryParse(coords[1], out lattitude)) return null;  
75.  
76.            return new Coords  
77.                       {  
78.                           Longitude = longitude,  
79.                           Latitude = lattitude  
80.                       };  
81.        }  
82.  
83.        public static double DistanceTo(this Coords from, Coords to, Units units)  
84.        {  
85.            // Haversine Formula...  
86.            var dLat1InRad = from.Latitude * (Math.PI / 180.0);  
87.            var dLong1InRad = from.Longitude * (Math.PI / 180.0);  
88.            var dLat2InRad = to.Latitude * (Math.PI / 180.0);  
89.            var dLong2InRad = to.Longitude * (Math.PI / 180.0);  
90.  
91.            var dLongitude = dLong2InRad - dLong1InRad;  
92.            var dLatitude = dLat2InRad - dLat1InRad;  
93.  
94.            // Intermediate result a.  
95.            var a = Math.Pow(Math.Sin(dLatitude / 2.0), 2.0) +  
96.                    Math.Cos(dLat1InRad) * Math.Cos(dLat2InRad) *  
97.                    Math.Pow(Math.Sin(dLongitude / 2.0), 2.0);  
98.  
99.            // Intermediate result c (great circle distance in Radians).  
100.            var c = 2.0 * Math.Atan2(Math.Sqrt(a), Math.Sqrt(1.0 - a));  
101.  
102.            // Unit of measurement  
103.            var radius = 6371;  
104.            if (units == Units.Miles) radius = 3959;  
105.  
106.            return radius * c;  
107.        }  
108.    }  
109.}  
/xml>

解决方案

If you load the XML in the browser, you'll see the following error message:

The Geocoding API v2 has been turned down on September 9th, 2013. The Geocoding API v3 should be used now. Learn more at https://developers.google.com/maps/documentation/geocoding/[^]

If you follow the link, you'll see a page with details on upgrading to v3:
https://developers.google.com/maps/articles/geocodingupgrade[^]

If you read through that, you'll find that you need to use the new endpoint:

"https://maps.googleapis.com/maps/api/geocode/xml?address={0}"

You have to use Google Maps & Places API to get the distance between two places. Check the link below on how to:

http://www.aspsnippets.com/Articles/Google-Maps-V3-Calculate-Distance-Travel-Duration-draw-plot-Route-and-display-Directions-between-two-locations.aspx[^]

这篇关于查找两个英国邮政编码之间的距离的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！