如何在android中以编程方式将数字放到textview中 [英] how to put a number to the textview programatically in android

问题描述

我正面临一个小而愚蠢的错误，我无法找到。在我的主类中，我声明了一个变量int a = 4;现在我想在textview中打印它。我写了下面的代码

 num1 =（TextView）findViewById（R.id.textView14）; 
 num1.setText（a）; 

当我运行程序时出现错误，说ResourceNotFoundException字符串ID



我可能犯的错误是什么？请引导我完成它

解决方案

setText [ ^ ]带有一个int参数，用于设置来自资源的文本，其中int是资源ID ...在您的情况下，它将查找id为4的资源 - 该资源不存在...

使用 .toString（） int类型的方法将数字转换为字符串...

将数字转换为字符串即

int num = 5;

字符串n = num +;



然后，

num1.setText（n）;



-KR

该错误表示找不到您使用的资源。



请检查你已经创建了一个 TextView 机智h id textView14 。



最后，换行：

 num1.setText（a）; 

to：

 num1.setText（a.toString（））; 

这是因为TextViews只接受String形式的文本。

i am facing a small and silly error which i am not able to find out. in my main class i declared a variable int a=4; now i want to print it in a textview. i wrote the following code

num1=(TextView) findViewById(R.id.textView14);
num1.setText(a);

when i run the program i get an error saying ResourceNotFoundException String ID

what can be the mistake that i have done? please guide me through it

解决方案

setText[^] with a single int parameter used to set the text from a resource where the int is the resource id...In your case it will look for the resource with id 4 - which does not exists...
Convert the number to string using .toString() method of the int type...

Convert the number to string i.e
int num = 5;
String n = num + "";

and then,
num1.setText(n);

-KR

Hi,

The error means a resource you've used couldn't be found.

Please check that you've created a TextView with the id of textView14.

Lastly, change the line:

num1.setText(a);

to:

num1.setText(a.toString());

This is because TextViews only accept text in form of String.

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