如何在表单上显示我的变量作为值？这是一个形式与$ Name $ Region $ Email $ Phone的价值形式 [英] How Do I Now Display My Variables As Values On A Form? That Is Produce A Form With The Values Of $Name $Region $Email $Phone

问题描述

if（isset（$ _ POST ['name']）=== true&& empty（$ _ POST ['name']）=== false）{

require'。 ./db/connect.php';



$ query = mysql_query（SElECT id FROM Customers WHERE Customer_Name ='。mysql_real_escape_string（trim（$ _ POST ['name '）））。'

）;





$ fred = mysql_result（$ query， 0，'id'）;

echo$ fred;







$ sql =SELECT * FROM Customers WHERE id ='$ fred';

$ results = mysql_query（$ sql）;

If（！$ results ）{

die（'无效查询：'。mysql_error（））;

}

while（$ result = mysql_fetch_array（$ results） ）{

$ name = $ result ['Customer_Name'];

$ region = $ result ['Physical_Region'];

$ Email = $ result ['Email_Address'];

$ phone = $ result ['Phone_Number'];



echo$ name;

echo$ region;

echo$ Emai l;

echo$ phone;

}



}

？>

if (isset($_POST['name'])=== true && empty($_POST['name'])=== false) {
require '../db/connect.php';

$query = mysql_query("SElECT id FROM Customers WHERE Customer_Name= '".mysql_real_escape_string(trim($_POST['name']))."'
");


$fred = mysql_result($query,0,'id' );
echo "$fred";



$sql = "SELECT * FROM Customers WHERE id='$fred'" ;
$results= mysql_query($sql);
If (!$results){
die('Invalid query:'.mysql_error());
}
while($result= mysql_fetch_array($results) ){
$name=$result['Customer_Name'];
$region=$result['Physical_Region'];
$Email=$result['Email_Address'];
$phone=$result['Phone_Number'];

echo"$name";
echo"$region";
echo"$Email";
echo"$phone";
}

}
?>

推荐答案

_POST ['name']）=== true&&空（

_POST['name'])=== true && empty(

_POST ['name']）=== false）{

需要'../db/connect.php';

_POST['name'])=== false) {
require '../db/connect.php';

query = mysql_query（SElECT id FROM Customers WHERE Customer_Name ='。mysql_real_escape_string（trim（

query = mysql_query("SElECT id FROM Customers WHERE Customer_Name= '".mysql_real_escape_string(trim(

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