在mfc中绕其中点旋转一条线 [英] Rotaing a Line Around its midpoint in mfc

问题描述

你好，



我想在mfc。中心周围旋转一条线。

这应该旋转当我点击鼠标移动它。

继承人的代码。

请帮我把。



其中NewPoint是鼠标点击点

和m_newStart是行起点

Hi there,

I'm tring to rotate a line in mfc., around its center.
this should be rotated as i click the mouse and move it.
heres the code for it.
please help me put.

where NewPoint is the mouse click point
and m_newStart is line start point

double distY=abs(m_NewPoint.y);
double distX=abs(m_NewPoint.x);
double theta=(abs(atan(distY/distX))*180/3.14);

m_newStart.x  = MdPt.x + (StPt.x-MdPt.x)*(cos(theta)) - (StPt.y-MdPt.y)*(sin(theta));
m_newStart.y  = MdPt.y  +  (-1)*(StPt.x-MdPt.x)*(sin(theta)) - (StPt.y-MdPt.y) * cos(theta));

m_newEnd.x  = MdPt.x -  (StPt.x-MdPt.x)*(cos(theta)) + (StPt.y-MdPt.y)*(sin(theta));
m_newEnd.y  = MdPt.y  -  (-1)*(StPt.x-MdPt.x)*(sin(theta)) + (StPt.y-MdPt.y)*(cos(theta));

推荐答案

通过此代码（java）计算X和Y.在C ++中使用sin和cos（包括math.h）。

Calculate X and Y by this code (java). Use sin and cos in C++ (include math.h).

 x = center + radius * Math.sin( angle );
 y = center - radius * Math.cos( angle );
}

这篇关于在mfc中绕其中点旋转一条线的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！