如何在windows c中使用http web请求上传文件＃ [英] How can upload files using http web request in windows c#

问题描述

您好专家，

我已经制作了一个Windows窗体应用程序和控制台exe也在这个我上传文件使用ftp web请求

但现在我想从它http web请求或htttps如何在c＃

中提出任何建议？

bcz ftp不安全。：（

Hello Experts,
I have made a windows form application and console exe also in this i am upload files using ftp web request
but now i want to it from http web request or htttps how it is possible in c#
any suggestion?
bcz ftp is not secured .:(

推荐答案

string URL = "http://"+HostIP+"/some/path/to/website";
string boundary = "----" + System.Guid.NewGuid();

string Dateiname = Path.GetFileName(FileName);

// Read file data
FileStream fs = new FileStream(FileName, FileMode.Open, FileAccess.Read);
byte[] data = new byte[fs.Length];
fs.Read(data, 0, data.Length);
fs.Close();

// Generate post objects
Dictionary<string,> postParameters = new Dictionary<string,>();
//postParameters.Add("name", "file");
postParameters.Add("file", new FormUpload.FileParameter(data, Dateiname, "application/octet-stream"));

// Create request and receive response
string postURL = URL;
string userAgent = "Someone";
HttpWebResponse webResponse = FormUpload.MultipartFormDataPost(postURL, userAgent, postParameters);

// Process response
StreamReader responseReader = new StreamReader(webResponse.GetResponseStream());
fullResponse = responseReader.ReadToEnd();
webResponse.Close();

连同

together with

public static class FormUpload
{
    private static readonly Encoding encoding = Encoding.UTF8;
    public static HttpWebResponse MultipartFormDataPost(string postUrl, string userAgent, Dictionary<string,> postParameters)
    {
        string formDataBoundary = String.Format("----------{0:N}", Guid.NewGuid());
        string contentType = "multipart/form-data; boundary=" + formDataBoundary;
        byte[] formData = GetMultipartFormData(postParameters, formDataBoundary);
        return PostForm(postUrl, userAgent, contentType, formData);
    }

    private static HttpWebResponse PostForm(string postUrl, string userAgent, string contentType, byte[] formData)
    {
        HttpWebRequest request = WebRequest.Create(postUrl) as HttpWebRequest;

        if (request == null)
        {
            throw new NullReferenceException("request is not a http request");
        }

        // Set up the request properties.
        request.Method = "POST";
        request.ContentType = contentType;
        request.UserAgent = userAgent;
        request.CookieContainer = new CookieContainer();
        request.ContentLength = formData.Length;

        // You could add authentication here as well if needed:
         request.PreAuthenticate = true;
         request.AuthenticationLevel = System.Net.Security.AuthenticationLevel.MutualAuthRequested;
         request.Headers.Add("Authorization", "Basic " + Convert.ToBase64String(System.Text.Encoding.Default.GetBytes("USER" + ":" + "PASSWORD")));

        // Send the form data to the request.


        using (Stream requestStream = request.GetRequestStream())
        {
            requestStream.Write(formData, 0, formData.Length);
            requestStream.Close();
        }
        return request.GetResponse() as HttpWebResponse;
    }

    private static byte[] GetMultipartFormData(Dictionary<string,> postParameters, string boundary)
    {
        Stream formDataStream = new System.IO.MemoryStream();
        bool needsCLRF = false;

        foreach (var param in postParameters)
        {
            // Thanks to feedback from commenters, add a CRLF to allow multiple parameters to be added.
            // Skip it on the first parameter, add it to subsequent parameters.
            if (needsCLRF)
                formDataStream.Write(encoding.GetBytes("\r\n"), 0, encoding.GetByteCount("\r\n"));

            needsCLRF = true;

            if (param.Value is FileParameter)
            {
                FileParameter fileToUpload = (FileParameter)param.Value;

                // Add just the first part of this param, since we will write the file data directly to the Stream
                string header = string.Format("--{0}\r\nContent-Disposition: form-data; name=\"{1}\"; filename=\"{2}\"\r\nContent-Type: {3}\r\n\r\n",
                    boundary,
                    param.Key,
                    fileToUpload.FileName ?? param.Key,
                    fileToUpload.ContentType ?? "application/octet-stream");

                formDataStream.Write(encoding.GetBytes(header), 0, encoding.GetByteCount(header));

                // Write the file data directly to the Stream, rather than serializing it to a string.
                formDataStream.Write(fileToUpload.File, 0, fileToUpload.File.Length);
            }
            else
            {
                string postData = string.Format("--{0}\r\nContent-Disposition: form-data; name=\"{1}\"\r\n\r\n{2}",
                    boundary,
                    param.Key,
                    param.Value);
                formDataStream.Write(encoding.GetBytes(postData), 0, encoding.GetByteCount(postData));
            }
        }

        // Add the end of the request.  Start with a newline
        string footer = "\r\n--" + boundary + "--\r\n";
        formDataStream.Write(encoding.GetBytes(footer), 0, encoding.GetByteCount(footer));

        // Dump the Stream into a byte[]
        formDataStream.Position = 0;
        byte[] formData = new byte[formDataStream.Length];
        formDataStream.Read(formData, 0, formData.Length);
        formDataStream.Close();

        return formData;
    }

    public class FileParameter
    {
        public byte[] File { get; set; }
        public string FileName { get; set; }
        public string ContentType { get; set; }
        public FileParameter(byte[] file) : this(file, null) { }
        public FileParameter(byte[] file, string filename) : this(file, filename, null) { }
        public FileParameter(byte[] file, string filename, string contenttype)
        {
            File = file;
            FileName = filename;
            ContentType = contenttype;
        }
    }

试用此代码： -



protected void Button1_Click（object sender，EventArgs e）

{



if（FileUpload1.HasFile）

{

uploadimage（FileUpload1，TextBox2）;

}



if（FileUpload2.HasFile）

{

uploadimage（FileUpload2，TextBox3）;

}



if（ FileUpload3.HasFile）

{

uploadimage（FileUpload3，TextBox4）;

}



if（FileUpload4.HasFile）

{

uploadimage（FileUpload4，TextBox5）;

}



if（FileUpload5.HasFile）

{

uploadimage（FileUpload5，TextBox6）;

}



if（FileUpload6.HasFile）

{

uploadimage（FileUpload6，TextBox7）;

}



ScriptManager.RegisterClientScriptBlock（this，this.GetType（），alertMessage，alert（'Pictures Uploaded Successfully'），true）;

}



public void uploadimage（FileUpload f1，TextBox t1）

{

string str = @data source = DEEPAKSHARMA-PC \ SQLEXPRESS;初始目录=新; integrated security = true;

SqlConnection con = new SqlConnection（str）;

con.Open（）;

string s = Server。 MapPath（Img /）+ f1.FileName;

f1.SaveAs（s）;

// SqlDataAdapter da = new SqlDataAdapter（从ddate选择计数（*）+ 1作为d，con）;

// int a = Convert.ToInt32（select（count（*）+ 1）dd from ddate）;



string query =插入date1 values（'+ TextBox1.Text +'，'+ f1.FileName +'，'+ t1.Text +'）;

SqlCommand cmd = new SqlCommand（query，con）;

cmd.ExecuteNonQuery（）;

con.Close（）;



}

Try this code:-

protected void Button1_Click(object sender, EventArgs e)
{

if (FileUpload1.HasFile)
{
uploadimage(FileUpload1,TextBox2);
}

if (FileUpload2.HasFile)
{
uploadimage(FileUpload2,TextBox3);
}

if (FileUpload3.HasFile)
{
uploadimage(FileUpload3,TextBox4);
}

if (FileUpload4.HasFile)
{
uploadimage(FileUpload4,TextBox5);
}

if (FileUpload5.HasFile)
{
uploadimage(FileUpload5,TextBox6);
}

if (FileUpload6.HasFile)
{
uploadimage(FileUpload6,TextBox7);
}

ScriptManager.RegisterClientScriptBlock(this, this.GetType(), "alertMessage", "alert('Pictures Uploaded Successfully')", true);
}

public void uploadimage(FileUpload f1, TextBox t1)
{
string str = @"data source=DEEPAKSHARMA-PC\SQLEXPRESS;initial catalog=new; integrated security=true";
SqlConnection con = new SqlConnection(str);
con.Open();
string s = Server.MapPath("Img/") + f1.FileName;
f1.SaveAs(s);
//SqlDataAdapter da = new SqlDataAdapter("Select count(*)+1 as d from ddate", con);
//int a = Convert.ToInt32("Select (count(*)+1) as d from ddate");

string query = "insert into date1 values('" + TextBox1.Text + "','" + f1.FileName + "','" + t1.Text + "')";
SqlCommand cmd = new SqlCommand(query, con);
cmd.ExecuteNonQuery();
con.Close();

}

这篇关于如何在windows c中使用http web请求上传文件＃的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！