用于读取下面给出的XML文件的C＃代码...想要读取节点值，如11111 for< ns0：Cell ns0：tableColumnName ="数字（带）“ NS0：colNo = QUOT; 2英寸;> 11111< / NS0：电池> [英] C# code to read the XML file given below... Want to read the node values like 11111 for <ns0:Cell ns0:tableColumnName=" number (with )" ns0:colNo="2">11111</ns0:Cell>

问题描述

< ns0：Root xmlns =urn：x-srid_data：namespacexmlns：ns0 =urn：x-srid_data：namespacens0：versionXML =1.0> 
< ns0：DOCUMENT ns0：name =C：\ Users \ddd \Desktop \ddd.dotx> 
< ns0：表ns0：name =化合物编号（带盐码）| ns0：tableNo =1ns0：WordTableGUID =a4133206-89eb-4771-b8bc-787011b742b9> 
< ns0：ROWS> 
< ns0：ROW ns0：rowNumber =1> 
< ns0：Cell ns0：tableColumnName =Unknownns0：colNo =1> Compound（with）< / ns0：Cell> 
< ns0：Cell ns0：tableColumnName =number（with）ns0：colNo =2> 11111< / ns0：Cell> 
< / ns0：ROW> 
< ns0：ROW ns0：rowNumber =2> 
< ns0：Cell ns0：tableColumnName =number（with）ns0：colNo =1>新数字< / ns0：Cell> 
< ns0：Cell ns0：tableColumnName =New numberns0：colNo =2> NEW NUMBER< / ns0：Cell> 
< / ns0：ROW> 
< ns0：ROW ns0：rowNumber =3> 
< ns0：Cell ns0：tableColumnName =number（with）ns0：colNo =1>上一个数字< / ns0：Cell> 
< ns0：Cell ns0：tableColumnName =Previous numberns0：colNo =2> PREVIOUS NUMBER< / ns0：Cell> 
< / ns0：ROW> 
< / ns0：ROWS> 
< / ns0：TABLE> 
< / ns0：DOCUMENT> 
< / ns0：Root> 

解决方案

您可以使用.NET FCL中提供的不同工具解析XML。这是我对他们的简短概述：

1. 使用 System.Xml.XmlDocument class 。它实现了DOM接口;如果文档的大小不是太大，这种方式是最简单和最好的。
   参见 http://msdn.microsoft.com/en-us/library/system.xml.xmldocument.aspx [ ^ ]。
2. 使用类 System.Xml.XmlTextReader ;这是最快的阅读方式，特别是你需要跳过一些数据。
   参见 http://msdn.microsoft.com/en-us/library/system.xml.xmlreader.aspx [ ^ ]。
3. 使用类 System.Xml.Linq.XDocument ;这是类似于 XmlDocument 的最合适的方式，支持LINQ to XML Programming。
   参见 http://msdn.microsoft.com/en-us/library/system.xml.xmldocument.aspx [ ^ ]，http://msdn.microsoft.com/en-us/library/bb387063.aspx [ ^ ]。

-SA

您可以使用Linq查询查找节点值并获取XML的所有值

<ns0:Root xmlns="urn:x-srid_data:namespace" xmlns:ns0="urn:x-srid_data:namespace" ns0:versionXML="1.0">
  <ns0:DOCUMENT ns0:name="C:\Users\ddd\Desktop\ddd.dotx">
    <ns0:TABLE ns0:name="Compound number (with salt code)|" ns0:tableNo="1" ns0:WordTableGUID="a4133206-89eb-4771-b8bc-787011b742b9">
      <ns0:ROWS>
        <ns0:ROW ns0:rowNumber="1">
          <ns0:Cell ns0:tableColumnName="Unknown" ns0:colNo="1">Compound  (with  )</ns0:Cell>
          <ns0:Cell ns0:tableColumnName=" number (with )" ns0:colNo="2">11111</ns0:Cell>
        </ns0:ROW>
        <ns0:ROW ns0:rowNumber="2">
          <ns0:Cell ns0:tableColumnName=" number (with  )" ns0:colNo="1">New  number</ns0:Cell>
          <ns0:Cell ns0:tableColumnName="New  number" ns0:colNo="2">NEW  NUMBER</ns0:Cell>
        </ns0:ROW>
        <ns0:ROW ns0:rowNumber="3">
          <ns0:Cell ns0:tableColumnName=" number (with  )" ns0:colNo="1">Previous  number</ns0:Cell>
          <ns0:Cell ns0:tableColumnName="Previous number" ns0:colNo="2">PREVIOUS  NUMBER</ns0:Cell>
        </ns0:ROW>
      </ns0:ROWS>
    </ns0:TABLE>
     </ns0:DOCUMENT>
</ns0:Root>

解决方案

You can parse XML using different facilities available in .NET FCL. This is my short overview of them:

1. Use System.Xml.XmlDocument class. It implements DOM interface; this way is the easiest and good enough if the size if the document is not too big.
   See http://msdn.microsoft.com/en-us/library/system.xml.xmldocument.aspx[^].
2. Use the class System.Xml.XmlTextReader; this is the fastest way of reading, especially is you need to skip some data.
   See http://msdn.microsoft.com/en-us/library/system.xml.xmlreader.aspx[^].
3. Use the class System.Xml.Linq.XDocument; this is the most adequate way similar to that of XmlDocument, supporting LINQ to XML Programming.
   See http://msdn.microsoft.com/en-us/library/system.xml.xmldocument.aspx[^], http://msdn.microsoft.com/en-us/library/bb387063.aspx[^].

—SA

You can use Linq query to find the node value and get all values of XML

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