弹出窗口的按钮未触发父页面按钮单击事件 [英] popup window's button not firing the parent page button click event

问题描述

我在父页面中有一个按钮ImageButton10。在弹出窗口中，出现一个OK按钮。我想在子页面或弹出窗口的OK按钮触发时触发ImageButton10_click事件。这该怎么做。请帮忙。



我的代码如下

儿童页面

I have a button ImageButton10 in a parent page. In the popup window a button OK is present. I want fire ImageButton10_click event when the OK button of child page or popup window will fire. how to do this. Please help.

My code is as follows
In child page

<script type="text/javascript" language="javascript">
    function RefreshParent() {
        document.getElementById('ImageButton10').Click();
        window.close();
    } 
</script>

<asp:Button ID="Button2" runat="server"  Text="Ok" 

            Width="123px" onclientClick="RefreshParent();" />

父母

Parent

protected void ImageButton10_Click(object sender, ImageClickEventArgs e)
    {
        con.Open();
        string query = "select distinct Contact_Name from Contact where Account='" + TextBox2.Text + "'";
        DataTable dt = new DataTable();
        SqlDataAdapter adpt = new SqlDataAdapter(query, con);
        adpt.Fill(dt);
        DropDownList6.DataSource = dt;
        DropDownList6.DataTextField = "Contact_Name";
        DropDownList6.DataValueField = "Contact_Name";
        DropDownList6.DataBind();
        con.Close();
        DropDownList6.Items.Insert(0, "<--Select-->");
    }

推荐答案

删除你的javascript代码，并将onclick属性添加到你的按钮，如下所示

remove your javascript code and add the onclick attribute to your button as below

<asp:button id="Button2" runat="server" text="Ok"

            Width="123px" OnClick="ImageButton10_Click"  ></asp:button>

你不想调用脚本调用服务器端代码。

you dont want to call script to calling the Server side code.

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