请检查以下语法并更正它有4个错误 [英] please check the below syntax and correct it it has 4 errors

问题描述

main()
{
    char *name;
    int  length;
    char *cptr = name;
    name = "DELHI";
    printf {"%s\n", name};
    while{*cptr != '\0'}
    {
     printf{"%C is stored at address %u\n", *cptr, cptr};
     cptr++;
     }
     length = cptr - name;
     printf{"\nLength of the string = %d\n", length};
}

推荐答案

为你固定。

Fixed for you.

#include <stdio.h>

int main()
{
    char *name;
    name = "DELHI";
    int  length;
    char *cptr = name;
    printf ("%s\n", name);
    while(*cptr != '\0')
    {
      printf("%C is stored at address %p\n", *cptr, cptr);
      cptr++;
    }
    length = cptr - name;
    printf("\nLength of the string = %d\n", length);
  return 0;
}

顺便说一句，你真的很喜欢花括号，不是吗？

By the way, you really like curly braces, don't you?

你系统地错放了{和}



第7行：printf {％s \ n，name}; - > printf（％s \ n，姓名）;

第8行：while {* cptr！='\ 0'} - > while（* cptr！='\ 0'）

第10行：printf {％C存储在地址％u \ n，* cptr，cptr}; - > printf（％C存储在地址％u \ n，* cptr，cptr）;



第14行：printf {\\\
Length of the string =％d \ n，length}; - > printf（字符串的\\\
Length =％d \ n，长度）;

You systematically misplaced "{" and "}"

Line 7: printf {"%s\n", name}; -> printf ("%s\n", name);
Line 8: while{*cptr != '\0'} -> while(*cptr != '\0')
Line 10: printf{"%C is stored at address %u\n", *cptr, cptr}; -> printf("%C is stored at address %u\n", *cptr, cptr);

Line 14: printf{"\nLength of the string = %d\n", length}; -> printf("\nLength of the string = %d\n", length);

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