React本机包更改未考虑在内 [英] React native bundle changes not taken in account

问题描述

我有一个使用此方法的组件：

I had a Component with this method :

onRegionChangeComplete = (region) => {
  var mapHeight = windowHeight - 124;

  var centerCircleLatitude = region.latitude + (mapHeight -  windowWidth  - (topSize * 2)) * (region.latitudeDelta / (2 * mapHeight));
  var centerCircleLongitude = region.longitude;

  RestaurantsActions.setRegion(radius, region.longitude, region.latitude, region.longitudeDelta, region.latitudeDelta, centerCircleLongitude, centerCircleLatitude, windowWidth, mapHeight);
  this.setState({data: RestaurantsStore.filteredRestaurants()});
  this.setState({isChanging : false});
  this.setState({index : 0});
  this.refs.carousel.goToPage(this.state.index, 'annotationPress');
}

我更改了上面的代码，删除了最后两行：

I changed the code above deleting the two last lines to :

onRegionChangeComplete = (region) => {
  var mapHeight = windowHeight - 124;

  var centerCircleLatitude = region.latitude + (mapHeight -  windowWidth  - (topSize * 2)) * (region.latitudeDelta / (2 * mapHeight));
  var centerCircleLongitude = region.longitude;

  RestaurantsActions.setRegion(radius, region.longitude, region.latitude, region.longitudeDelta, region.latitudeDelta, centerCircleLongitude, centerCircleLatitude, windowWidth, mapHeight);
  this.setState({data: RestaurantsStore.filteredRestaurants()});
  this.setState({isChanging : false});
}

运行react-native bundle时，我检查输出文件，它仍然有我删除了那两行。是否有缓存或剩余的东西？

When running react-native bundle, I check the output file and it still has those two lines I deleted. Is there a cache or something remaining ?

我的捆绑命令行：

react-native bundle --dev true --entry-file index.ios.js --bundle-output ios/main.jsbundle --verbose --platform ios

我正在使用react-native 0.16.0

I'm using react-native 0.16.0

推荐答案

好的，我发现，捆绑包使用了打包器的缓存版本。我通过这样做删除了它：

OK, I found out, the bundle used a cache version of the packager. I removed it by doing :

rm -f $TMPDIR/react-packager*

然后我重新运行了bundle命令，它工作正常。

Then I re-runnned the bundle command and it worked fine.

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