c＃串口通讯 [英] c# Serial Communication

问题描述

我在c＃中编写了一个代码，用于通过串行通信接收数据并将其显示在文本框中。我能够做到这一点。但我收到以下格式的数据，例如



1234 2345 3456 5667

或



1234 3245 5678

但我希望每个传入的字节都应该覆盖前一个字节，在文本框中我们只能看到1个字节，然后是另一个字节覆盖前一个字节。 />


请建议怎么做？



我的ser comm代码如下：

I have written a code in c# for receiving data through serial communication and display it in a text box. I am able to do that. But I am receiving data in following format, e.g.

1234 2345 3456 5667
or

1234 3245 5678
But I want that every incoming byte should overwrite the previous byte and in the text box we should see just 1 byte and then another byte overwriting the previous one.

Please suggest how to do that?

My code for ser comm is as follows :

private void SerialPort_DataReceived(object sender, System.IO.Ports.SerialDataReceivedEventArgs e) 
{ 
    RxString = SerialPort.ReadExisting(); 
    this.Invoke(new EventHandler(DisplayText)); }

private void DisplayText(object sender, EventArgs e)
{
    txtIncomingData.AppendText(RxString);
}

推荐答案

你误解了 Control.Invoke 。这不是事件调用，因此您的对象发送者和 EventArgs 参数是多余的。有了这个假设的人为限制，你做了一件坏事：将文本传递给相对于你的方法的外部上下文。相反，您应该使用您需要的任何签名的事件委托：

You misunderstood Control.Invoke. This is not event invocation, so your object sender and EventArgs arguments are superfluous. Having this made-up artificial limitation, you have done bad thing: passing the text through the outer context relative to your method. Instead, you should use the event delegate with any signature you need:

string newData = SerialPort.ReadExisting(); // local variable to be used in next line
this.Invoke(new System.Action<string>((data) => {
   txtIncomingData.AppendText(data);
}), newData);

如果你需要覆盖字符，不要附加，假设 txtIncomingData 是你的文本框，替换

If you need to override the character, not append, assuming txtIncomingData is you text box, replace

txtIncomingData.AppendText(data);

with

with

txtIncomingData.Text = data;

-SA

下面的解决方案有效，但它在数据之间提供空白字节。

The solution below works, but it gives blank bytes in between data.

    SerialPort serialPort;

    private delegate void SetTextDeleg(string text);

    private void Form1_Load(object sender, EventArgs e)
    {
          serialPort= new SerialPort("COM6", 4800, Parity.None, 8, StopBits.One);
          serialPort.Handshake = Handshake.None;
          serialPort.DataReceived += new SerialDataReceivedEventHandler(sp_DataReceived);
          serialPort.ReadTimeout = 500;
          serialPort.WriteTimeout = 500;
          serialPort.Open();
}

private void btnStart_Click(object sender, EventArgs e)
{
      try
      {
           if(!serialPort.IsOpen)
                serialPort.Open();
      }
      catch (Exception ex)
      {
           MessageBox.Show("Could not open Serial Port");
      }
}

void sp_DataReceived(object sender, SerialDataReceivedEventArgs e)
{
     Thread.Sleep(500);
     string data = serialPort.ReadLine();
     this.BeginInvoke(new SetTextDeleg(si_DataReceived), new object[] { data });
}

private void si_DataReceived(string data)
{
      txtIncomingData.Text = data.Trim();
}

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