试着只在这段代码中接收奇数？ [英] Trying to only receive odd numbers in this bit of code?

问题描述

它在奇数的第一个实例中起作用，但是一旦用户输入另一个，它就输出Magic Box＃>（它们的数字）<。我这段代码只接收奇数。请帮帮我。

It works in the first instance of an odd number, but as soon as the user inputs another one it outputs Magic Box# >(their number)<. I this bit of code only to receive odd numbers. Please help me.

#include<iostream>
#include<fstream>
#include<iomanip>
using namespace std;

ofstream outfile;
ifstream infile;
int main()
{
    outfile.open("output.txt");
    infile.open("numbers.txt");
    int n, row, column; //intermediate variable and row and column variables
    cout << "Welcome to  the Magic Square Program!" << endl << endl;
    infile >> n;
        if (n % 2 == 0)
        {
            cout << "Odd numbers only, Please enter an odd number:" << endl;
            cin >> n;
            goto Odd;
        }
        else
        {
            Odd:
            cout << "Magic Box#: " << " > " << n << " <" << endl << endl;
        }


        int MagicSquare[3][3];
        MagicSquare[0][2] = 1;

        for (int x = 0; x < n; x++)
        {
            for (int y = 0; y < n; y++){
            //  cout << setw(3) << x * y << MagicSquare[x][y];
            }
            cout << endl;
        }

system("pause");
    return 0;
}

推荐答案

1。从来没有在C ++中使用goto



2.用以下代码替换输入代码：

1. never ever use goto in C++

2. Replace your input code with this:

int n;
do {
   cout >> "Plase enter an odd number: " << endl;
   cin >> n;
} while (n%2 != 0);

3.一旦按预期工作，用一些额外的检查（如负数或非数字输入）充实该代码

3. once it works as intended, flesh out that code with some extra checks, like negative numbers, or non-numeric input

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