如何从时间上剥离日期 [英] How to strip date from time
本文介绍了如何从时间上剥离日期的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想只显示日期,我尝试这样;
I want to show only the date, I try like this;
$("#popupEventForm").find("form").find("#eventDate").val(calEvent.start).toString("MM/dd/yy");
这是C#属性:
this is are C# properties:
public JsonResult GetDiarySummary(double start, double end, string Title)
{
var ApptListForDate = DiaryEvent.LoadAppointmentSummaryInDateRange(start, end, Title);
var eventList = from e in ApptListForDate
select new
{
id = e.ID,
title = e.Title,
appointmentLength = e.AppointmentLength,
start = e.StartDateString.FormatWith("MM/dd/yy"),
scheduledTime = e.StartDateString,
end = e.EndDateString,
someKey = e.SomeImportantKeyID,
allDay = false
};
var rows = eventList.ToArray();
return Json(rows, JsonRequestBehavior.AllowGet);
}
推荐答案
( #popupEventForm)。find( form)。find ( #eventDate)。val(calEvent.start).toString( MM / dd / yy);
("#popupEventForm").find("form").find("#eventDate").val(calEvent.start).toString("MM/dd/yy");
这是C#属性:
this is are C# properties:
public JsonResult GetDiarySummary(double start, double end, string Title)
{
var ApptListForDate = DiaryEvent.LoadAppointmentSummaryInDateRange(start, end, Title);
var eventList = from e in ApptListForDate
select new
{
id = e.ID,
title = e.Title,
appointmentLength = e.AppointmentLength,
start = e.StartDateString.FormatWith("MM/dd/yy"),
scheduledTime = e.StartDateString,
end = e.EndDateString,
someKey = e.SomeImportantKeyID,
allDay = false
};
var rows = eventList.ToArray();
return Json(rows, JsonRequestBehavior.AllowGet);
}
我解决了,就像这样:
I solved, like this:
rec.StartDateString = item.DateTimeScheduled.ToString("MMMM/dd/yyyy");
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