关于Apriori算法的XQuery实现 [英] On XQuery implementation of Apriori algorithm

问题描述

我正在尝试通过Apriori算法从XML文档中挖掘关联规则。这样做有两种通用方法：1）将XML映射到关系格式并应用经典的Apriori，2）直接挖掘XML。我想使用后者，但有几个问题。



经过研究，我发现了一篇论文，提出了XQuery模拟Apriori。尽管如此，提供的代码没有集成，因为我是XQuery的新手，我无法运行该程序。我认为有一些我不知道的提示。

I’m trying to mine association rules from XML documents by Apriori algorithm. Doing so, there are two general approaches: 1) mapping XML to relational format and applying classical Apriori, 2) mining XML directly. I’d like to use the latter one but there are several problems.

After researching, I’ve found a paper that proposes a simulation of Apriori by XQuery. Nonetheless, the provided codes are not integrated and since I'm new to XQuery, I couldn't run the program. I think there are some tips that I'm unaware of.

define function join(element $X, element $Y) returns element {
let $items := (for $item in $Y
where every $i in $X satisfies
$i != $item
return $item)
return $X union $items
}

define function commonIts(element $X, element $Y) returns
element {
for $item in $X
where some $i in $Y satisfies $i = $item
return $item
}

define function removeIts(element $X, element $Y) returns
element {
for $item in $X
where every $i in $Y satisfies $i != $item
return $item
}

define function candidateGen(element $l) returns element {
for $freqSet1 in $l
let $items1 := $freqSet1//items/*
for $freqSet2 in $l
let $items2 := $freqSet2//items/*
where $freqSet2 >> $freqSet1 and
count($items1)+1 =  count($items1 union $items2)
and prune(join($items1,$items2), $l)
return <items>
{join($items1,$items2)}
</items>
}

define function prune(element $X, element $Y) returns boolean
{
every $item in $X satisfies
some $items in $Y//items satisfies
count(commonIts(removeIts($X,$item),$items/*))
= count($X) - 1
}

define function removeDuplicate(element $C) returns element
{
for $itemset1 in $C
let $items1 := $itemset1/*
let $items :=(for $itemset2 in $C
let $items2 := $itemset2/*
where $itemset2>>$itemset1 and
count($items1) =
count(commonIts($items1, $items2))
return $items2)
where count($items) = 0
return $itemset1
}

define function getLargeItemsets(element $C, element $minsup,
element $total, element $src) returns element {
for $items in $C
let $trans := (for $tran in $src
where every $item1 in $items/* satisfies
some $item2 in $tran/*
satisfies $item1 = $item2
return $tran)
let $sup := (count($trans) * 1.00) div $total
where $sup >= $minsup
return <largeItemset> {$items}
<support> {$sup} </support>
</largeItemset>
}

define function apriori(element $l, element $L, element $minsup,
element $total, element $src) returns element {
let $C := removeDuplicate(candidateGen($l))
let $l := getLargeItemsets($C, $minsup, $total, $src)
let $L := $l union $L
return if (empty($l)) then
$L
else
apriori($l, $L, $minsup, $total, $src)
}

let $src := document("/transactions.xml")//items
let $minsup := 0.4
let $items := (for $item in $src/*
where $itemset = $item
let $total := count($src) * 1.00
let $C := distinct-values($src/*)
let $l :=(for $itemset in $C
return $item)
let $sup := (count($items) * 1.00) div $total
where $sup >= $minsup
return <largeItemset>
<items> {$itemset} </items>
<support> {$sup} </support>
</largeItemset>)
let $L := $l
return <largeItemsets> { apriori($l, $L,$minsup, $total, $src) }
</largeItemsets>

来计算规则文档，他们介绍了这个表达式：

to compute rule documents, they introduced this expression:

let $minconf := 1.00
let $src := document("/large.xml")//largeItemset
for $itemset1 in $src
let $items1 := $itemset1/items/*
for $itemset2 in $src
let $items2 := $itemset2/items/*
where count($items1) > count($items2) and
count(commonIts($items1, $items2)) =
count($items2) and $itemset1/support div
$itemset2/support >= $minconf
return <rule support ="{$itemset1/support}"

confidence = "{($itemset1/support*1.0) div
($itemset2/support*1.0)}">
<antecedent> {$items2} </antecedent>
<consequent>
{removeItems($items1,$items2)}
</consequent>
</rule>

样本数据集如下：

The sample data set is as follows:

<transactions>
<transaction id="1">
 <items>
<item>a</item> 
<item>d</item>
<item>e</item>
 </items>
</transaction>

<transaction id="2">
 <items>
<item>b</item> 
<item>c</item>
<item>d</item>
 </items>
</transaction>

<transaction id="3">
 <items>
<item>a</item> 
<item>c</item>
 </items>
</transaction>

<transaction id="4">
 <items>
<item>b</item> 
<item>c</item>
<item>d</item>
 </items>
</transaction>

<transaction id="5">
 <items>
<item>a</item> 
<item>b</item>
 </items>
</transaction>

</transactions>

现在，对我来说最大的挑战是将这些功能集成在一起工作。

Now, the big challenge for me is to integrate these functions together to work.

推荐答案

X，element

X, element

Y）返回元素{
let

Y) returns element { let

items：=（对于

items := (for

这篇关于关于Apriori算法的XQuery实现的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！