如何从webservice返回xml [英] how to return xml from webservice

问题描述

我想从xml document.document构建一个web服务就像这样

i am tring to build a webservice from xml document.document is like this

<?xml version="1.0" encoding="UTF-8" ?> 
- <!--  Generated on Sat, 17 Dec 2011 16:40:23 +0530 
  --> 
- <rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom">
- <channel>
  <atom:link href="http://www.business-standard.com/rss/rss_icon.png" rel="self" type="application/rss+xml" /> 
- <title>
- <![CDATA[ Markets & Investing ->News Now
   
  </title>
  <link>http://www.business-standard.com/</link> 
  <description>The latest news from India's most respected business daily.</description> 
  <language>en-us</language> 
  <managingEditor>[e-mail] (Webmaster)</managingEditor> 
  <webMaster>[e-mail] (Webmaster)</webMaster> 
  <generator>PHP RSS Feed Generator</generator> 
- <image>
  <url>http://www.business-standard.com/india/images/logo_08.jpg</url> 
  <title>Business-Standard</title> 
  <link /> 
  <width>248</width> 
  <height>146</height> 
  </image>
- <item>
- <title>
- <![CDATA[ Gold snaps 5-day losing streak, gains Rs 75

   

  </title>
- <description>
- <![CDATA[ Snapping five-day losing streak, gold prices recovered Rs 75 to Rs 27,840 per 10 gram in the national capital today on buying at lower levels amid firm trend overseas.

   

  </description>
  <link>http://www.business-standard.com/india/news/gold-snaps-5-day-losing-streak-gains-rs-75/153154/on</link> 
  <pubDate>Sat, 17 Dec 2011 15:38:06 +0530</pubDate> 
  <guid isPermaLink="true">http://www.business-standard.com/india/news/gold-snaps-5-day-losing-streak-gains-rs-75/153154/on</guid> 
  </item>

。我正在做的事情是

.next thing i am doing is
in

public class Service1 : IService1
   {
       public string gettitle()
       {
           XmlDocument xd = new XmlDocument();
           xd.LoadXml(@"D:\satish\satti.xml");
           XmlNodeList XmlNodeListObj = xd.GetElementsByTagName("//title");
           return XmlNodeListObj.ToString ();
       }

也在iservice类我写了相应的方法，

服务托管与操作一样gettitle（），当我试图调用该服务时，它表示rootelement中的数据无效，

也是如何纠正该错误。

我可以得到存储的wcf通过编写ds.writexml（path）;

also in the iservice class i wrote that corresponding method,
the service is hosted with operations as gettitle(),when i triesd to invoke that service it is saying data at rootelement is invalid,
also how to get that error rectified .
can i get that wcf stored as xml by writing ds.writexml(path);

推荐答案

作为xml，你已经在XmlDocument中加载了XML。现在直接返回XmlDocument的对象。不要尝试返回XML。

you have loaded you XML in XmlDocument. now just return XmlDocument's object directly. do not try to return XML.

XmlDocument xd = new XmlDocument();
xd.LoadXml(@"D:\satish\satti.xml");
return xd;

如果我返回xmldocument没有用，我想将上面的xml文档排除以获取标题并将该内容作为wcf服务返回，这里发生的主要事情是if我查询，这是作为字符串返回

if i return xmldocument no use, i want to querty the xml document above to get title only and return that thing as wcf service,the main thing happening here is if i queried ,that is returning as strings

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