如何检测两个面板的重叠区域。 [英] How to detect overlapped area of two panels.

问题描述

我有两个不同宽度的可调整大小的面板。重新调整大小，如果他们重叠，那么我想只获得重叠区域。我试着检测重叠面板，但不知道如何获得重叠区域（宽度）。

 Rectangle sr =  new  Rectangle（panel1.Left，panel1.Top，panel1.Width，panel1.Height）; 
  foreach （控制ctrl   此 .Controls）
 {
  if （ctrl   Panel&& ; ctrl！= panel1）
 {
 Rectangle r =  new 矩形（ctrl.Left，ctrl.Top，ctrl.Width，ctrl.Height ）; 
  if （sr.IntersectsWith（r））
 {
  //  这里我只想要ctrl的重叠区域（宽度）。 
} 
} 
} 

如有任何想法请分享。

解决方案

致电 Rectangle.Intersect方法（矩形，矩形） [ ^ ]获取交叉矩形然后使用其宽度属性。

  if （sr .IntersectsWith（r））
 {
 Rectangle rectangle3 = Rectangle.Intersect（sr，r）; 
  //   rectangle3表示两个其他Rectangle结构的交集 
} 

您可以简化代码：

  //  需要LInq  
 使用 System.Linq 
 
  private   void  getIntersection（Panel targetPanel，Control containerToSearch）
 {
 Rectangle targetBounds = targetPanel.Bounds; 
 
 Rectangle testIntersect; 
 
  foreach （Panel thePanel  in  containerToSearch.Controls.OfType< Panel>（ ））
 {
  if （thePanel == targetPanel） continue ; 
 
 testIntersect = Rectangle.Intersect（targetBounds，thePanel.Bounds）; 
 
  if （testIntersect！= Rectangle.Empty）
 {
  //  仅供测试 
 Console.WriteLine（ 面板名称：{0} \r\\\
intersection：{1}，thePanel.Name，testIntersect.ToString（））; 
 
  //  无论你需要做什么...  
 
  //  当您找​​到第一个交叉面板时停止 
 断裂; 
} 
} 
} < /   panel  >  

I have two re-sizable panels having different width. on re-sizing if they get overlapped then i want to get only overlapped area. I tried following to detect overlapped panels, but not idea about how to get overlapped area(width).

Rectangle sr = new Rectangle(panel1.Left, panel1.Top, panel1.Width, panel1.Height);
foreach (Control ctrl in this.Controls)
{
	if (ctrl is Panel && ctrl != panel1)
	{
		Rectangle r = new Rectangle(ctrl.Left, ctrl.Top, ctrl.Width, ctrl.Height);
		if (sr.IntersectsWith(r))
		{
			//here i want only the overlapped area(width) of ctrl.
		}
	}
}

if have any idea please share.

解决方案

Call the Rectangle.Intersect Method (Rectangle, Rectangle)[^] to get the intersection rectangle and then use its Width property.

if (sr.IntersectsWith(r))
{
   Rectangle rectangle3 = Rectangle.Intersect(sr, r);
   //rectangle3 represents the intersection of two other Rectangle structures
}

You can simplify your code:

// requires LInq
using System.Linq

private void getIntersection(Panel targetPanel, Control containerToSearch)
{
    Rectangle targetBounds = targetPanel.Bounds;

    Rectangle testIntersect;

    foreach (Panel thePanel in containerToSearch.Controls.OfType<Panel>())
    {
        if (thePanel == targetPanel) continue;

        testIntersect = Rectangle.Intersect(targetBounds, thePanel.Bounds);
        
        if (testIntersect != Rectangle.Empty)
        {
            // for testing only
            Console.WriteLine("panel name: {0} \r\nintersection: {1}", thePanel.Name, testIntersect.ToString());

            // whatever else you need to do ...

            // stop when you find the first intersecting Panel
            break;
        }
    }
}</panel>

这篇关于如何检测两个面板的重叠区域。的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！