为什么我会收到java.io.IOException异常：标记已失效？ [英] Why am I getting java.io.IOException: Mark has been invalidated?
问题描述
我想下载从URL imags，然后去$ C C他们$。 问题是，我不知道他们有多大，如果我去$ C C $他们马上，应用程序崩溃，过于大的图像。
我做以下和它的工作原理与大多数图像，但其中的一部分，它抛出了 java.io.IOException异常：标记已失效例外。
这不是大小的问题，因为它具有75KB或120KB的图像，而不是用一个20MB或45KB的图像会发生。
同样的格式并不重要，因为它可以发生无论是与一个JPG或PNG图片。
PIS 是的InputStream 。
选项选择采用=新BitmapFactory.Options（）;
的BufferedInputStream双=新的BufferedInputStream（PIS）;
bis.mark（1024 * 1024）;
opts.inJustDe codeBounds = TRUE;
位图bmImg = BitmapFactory.de codeStream（之二，空，选择采用）;
Log.e（optwidth，opts.outWidth +）;
尝试 {
bis.reset（）;
opts.inJustDe codeBounds = FALSE;
INT比= opts.outWidth / 800;
Log.e（比率，将String.valueOf（比））;
如果（opts.outWidth＆GT; = 800）opts.inSampleSize =比;
返回BitmapFactory.de codeStream（之二，空，选择采用）;
}赶上（IOException异常E）{
// TODO自动生成的catch块
e.printStackTrace（）;
返回null;
}
我想你想脱code大的图像。我选择展厅形象做到了。
文件照片=新的文件（imageFilePath您选择）;
位图B =去codeFILE（照片）;
德codeFILE（张）功能用于去code大的图像。我想你需要获得图像的.png或.jpg formet。
私人位图德codeFILE（文件f）{
尝试 {
//德code图像尺寸
BitmapFactory.Options O =新BitmapFactory.Options（）;
o.inJustDe codeBounds = TRUE;
BitmapFactory.de codeStream（新的FileInputStream（f）项，空，O）;
//找到正确的比例值。它应该是2的幂。
最终诠释REQUIRED_SIZE = 70;
INT width_tmp = o.outWidth，height_tmp = o.outHeight;
int标= 1;
而（真）{
如果（width_tmp / 2'; REQUIRED_SIZE || height_tmp / 2'; REQUIRED_SIZE）
打破;
width_tmp / = 2;
height_tmp / = 2;
规模++;
}
//德code与inSampleSize
BitmapFactory.Options O2 =新BitmapFactory.Options（）;
o2.inSampleSize =规模;
返回BitmapFactory.de codeStream（新的FileInputStream（f）项，空，O2）;
}赶上（FileNotFoundException异常E）{}
返回null;
}
您可以通过使用ImageView的显示出来。
ImageView的IMG =（ImageView的）findViewById（R.id.sdcardimage）;
img.setImageBitmap（B）;
I'm trying to download imags from a url and then decode them. The problem is that I don't know how large are they and if I decode them right away, the app crashes with too-big images.
I'm doing the following and it works with most of the images but with some of them, it throws the java.io.IOException: Mark has been invalidated exception.
It's not a matter of size because it happens with a 75KB or a 120KB image and not with a 20MB or 45KB image.
Also the format is not important as it can happen either with a jpg or png image.
pis is an InputStream.
Options opts = new BitmapFactory.Options();
BufferedInputStream bis = new BufferedInputStream(pis);
bis.mark(1024 * 1024);
opts.inJustDecodeBounds = true;
Bitmap bmImg=BitmapFactory.decodeStream(bis,null,opts);
Log.e("optwidth",opts.outWidth+"");
try {
bis.reset();
opts.inJustDecodeBounds = false;
int ratio = opts.outWidth/800;
Log.e("ratio",String.valueOf(ratio));
if (opts.outWidth>=800)opts.inSampleSize = ratio;
return BitmapFactory.decodeStream(bis,null,opts);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
return null;
}
I think you want to decode large image. I did it by selecting gallery image.
File photos= new File("imageFilePath that you select");
Bitmap b = decodeFile(photos);
"decodeFile(photos)" function is used for decode large image. I think you need to get image .png or .jpg formet.
private Bitmap decodeFile(File f){
try {
//decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
BitmapFactory.decodeStream(new FileInputStream(f),null,o);
//Find the correct scale value. It should be the power of 2.
final int REQUIRED_SIZE=70;
int width_tmp=o.outWidth, height_tmp=o.outHeight;
int scale=1;
while(true){
if(width_tmp/2<REQUIRED_SIZE || height_tmp/2<REQUIRED_SIZE)
break;
width_tmp/=2;
height_tmp/=2;
scale++;
}
//decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize=scale;
return BitmapFactory.decodeStream(new FileInputStream(f), null, o2);
} catch (FileNotFoundException e) {}
return null;
}
you can display it by using imageView.
ImageView img = (ImageView)findViewById(R.id.sdcardimage);
img.setImageBitmap(b);
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