c＃从xml中获取cant元素 [英] c# get cant element from xml

问题描述

我做youtube请求，我得到xml流结果我将streamResult

传递给Xdocument，我设法将所有带有spance名称的参数都这样：

 durations = doc.Descendants（xmlNameSpace +content）....... 
 

但是我发布的已发布元素值是xml：

< feed xmlns = http://www.w3.org/2005/Atom\".......> 
< id> http：//gdata.youtube.com/feeds/api/videos< / id> 
< updated> 2014-07-15T11：19：24.176Z< / updated> 
< category scheme =http://schemas.google.com/g/2005#kind> 
< link rel =http://schemas.google.com/g/2005#feedtype =application / atom + xmlhref =http://gdata.youtube.com/feeds/ api / videos/> 
  - < author> 
< name> YouTube< / name> 
< uri> http：//www.youtube.com/< / uri> 
< / author> 
< generator version =2.1uri =http://gdata.youtube.com> YouTube数据API< / generator> 
< openSearch：totalResults> 125170< / openSearch：totalResults> 
< openSearch：startIndex> 1< / openSearch：startIndex> 
< openSearch：itemsPerPage> 25< / openSearch：itemsPerPage> 
  - < entry> 
< id> http：//gdata.youtube.com/feeds/api/videos/GIk6kSdeIsA< / id> 
< Published> 2011-09-21T10：31：53.000Z< / published> 
< updated> 2014-07-14T23：05：54.000Z< / updated> 
 .....< entry> 

i托盘此代码maby：

列表与LT;&的XElement GT; node = doc.Root.Descendants（entry）。ToList（）; 
 

请helppp：）

解决方案

请查看以下链接，这可能有助于您了解使用C＃读取和编写XML。

如何：使用XmlReader解析XML [ ^ ]

C# XmlReader [ ^ ]

如何在C＃中打开和读取XML文件 [ ^ ]

i do youtube request and i get the xml stream result i pass the "streamResult"
to "Xdocument" , I managed to take all the parameters with the name spance like this :

durations = doc.Descendants(xmlNameSpace + "content").......

but the "published" element value i cant take this is the xml:

<feed xmlns="http://www.w3.org/2005/Atom".......>
  <id>http://gdata.youtube.com/feeds/api/videos</id> 
  <updated>2014-07-15T11:19:24.176Z</updated> 
  <category scheme="http://schemas.google.com/g/2005#kind">
  <link rel="http://schemas.google.com/g/2005#feed" type="application/atom+xml" href="http://gdata.youtube.com/feeds/api/videos" /> 
- <author>
  <name>YouTube</name> 
  <uri>http://www.youtube.com/</uri> 
  </author>
  <generator version="2.1" uri="http://gdata.youtube.com">YouTube data API</generator> 
  <openSearch:totalResults>125170</openSearch:totalResults> 
  <openSearch:startIndex>1</openSearch:startIndex> 
  <openSearch:itemsPerPage>25</openSearch:itemsPerPage> 
- <entry>
  <id>http://gdata.youtube.com/feeds/api/videos/GIk6kSdeIsA</id> 
  <published>2011-09-21T10:31:53.000Z</published> 
  <updated>2014-07-14T23:05:54.000Z</updated> 
  .....<entry>

i tray this code maby:

List<XElement> node = doc.Root.Descendants("entry").ToList();

please helppp :)

解决方案

Hi,

Kindly review below link, which may help you to understand reading and writing XML with C#.
How to: Parse XML with XmlReader[^]
C# XmlReader[^]
How to open and read XML file in C#[^]

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