如何在jq grid和json的帮助下表示数据库中的数据？ [英] how to represent data from database with the help of jq grid and json ?

问题描述

我有一个与jgrid有关的问题...

嗨我正在使用webservice和所有的web服务和所有jgrid工作正常，我的价值也来到浏览器（firebug） ...但在此之后我无法在网格中显示到我的页面...

i有一个带有4个参数的表（Id，Name，EmailId，Location）

Hi, i have a issue related to jgrid ...
hi i am using webservice and all the web service and all the jgrid are working good and my value also comes to browser (firebug)... but after this i can't show in grid to my page...
i have a table with 4 parameter (Id,Name,EmailId,Location)

$.ajax({
            type: "POST",
            contentType: "application/json; charset=utf-8",
           url: "DesktopModules/Shopism_Anupam/anupamWebService.asmx/GridList",
            data: "{}",
            dataType: "json",
            success: function (data) {
                alert("hi");
            },
            error: function (result) {
                alert("Error");
            }
        });

之后我检查我在firebug的价值，但在此之后我什么也做不了......

请帮助....

after this i check my value at firebug but i can't do anything after this...
please help....

推荐答案

.ajax （{
类型：POST，
contentType：application / json; charset = utf-8，
url：DesktopModules / Shopism_Anupam / anupamWebService.asmx / GridList，
data：{}，
dataType：json，
success：function（data）{
alert（hi）;
}，
error：function（result）{
alert（Error）;
}
}）;

.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: "DesktopModules/Shopism_Anupam/anupamWebService.asmx/GridList", data: "{}", dataType: "json", success: function (data) { alert("hi"); }, error: function (result) { alert("Error"); } });

之后我在firebug检查我的价值，但在此之后我什么也做不了......

请帮帮....

after this i check my value at firebug but i can't do anything after this...
please help....

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