获取要打印的JSON函数 [英] Get a JSON function to print out
本文介绍了获取要打印的JSON函数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试打印JSON函数。
设计或调试时没有错误消息。
它只是没有打印出JSON。
另外一个问题:存储后JSON数据会在哪里发生?
I am trying to get a JSON function to print out.
There are no error messages when designing or debugging.
It just did not print out the JSON.
One additional question: Where does the JSON data go after you store it?
<script type="text/javascript">
function ListJSON() {
var obj = [
{"name":"name1","street":"street1","city":"city1","state":"state1","zip":"zip1","phone":"phone1"},
{"name":"name2","street":"street2","city":"city2","state":"state2","zip":"zip2","phone":"phone2"},
{"name":"name3","street":"street3","city":"city3","state":"state3","zip":"zip3","phone":"phone3"}
];
var name1 = document.getElementById("<%=TextBox1.ClientID%>").text
var street1 = document.getElementById("<%=TextBox2.ClientID%>").text
var city1 = document.getElementById("<%=TextBox3.ClientID%>").text
var state1 = document.getElementById("<%=TextBox4.ClientID%>").text
var zip1 = document.getElementById("<%=TextBox5.ClientID%>").text
var phone1 = document.getElementById("<%=TextBox6.ClientID%>").text
//var text = '{"name":name1,"street":street1,"city":city1,"state":state1,"zip":zip1,"phone":phone1}'
n = obj.length + 1;
obj[n].name = name1;
obj[n].street = street1;
obj[n].city = city1;
obj[n].state = state1;
obj[n].zip = zip1;
obj[n].phone = phone1;
var out = "<table><tr><td>";
var i;
for (i = 0; i < obj.length; i++) {
out += 'obj[i].name + "</td><td>" + obj[i].street + "</td><td>" + obj[i].city + "</td><td>" + obj[i].state + "</td><td>" + obj[i].zip + "</td><td>" + obj[i].phone + "</td></tr><tr><td>"';
}
out += "</td></tr></table></center>"
document.getElementById("id01").innerHTML = out;
}
</script>
<div><center><table><tr><td><br/><br/><br/>
<asp:Label ID="Label1" runat="server" Text="Name"></asp:Label></td></tr><tr><td>
<asp:TextBox ID="TextBox1" runat="server" Text="Jack Ertle"></asp:TextBox></td></tr><tr><td>
<asp:Label ID="Label2" runat="server" Text="Street"></asp:Label></td></tr><tr><td>
<asp:TextBox ID="TextBox2" runat="server" Text="Street"></asp:TextBox></td></tr><tr><td>
<asp:Label ID="Label3" runat="server" Text="City"></asp:Label></td></tr><tr><td>
<asp:TextBox ID="TextBox3" runat="server" Text="City"></asp:TextBox></td></tr><tr><td>
<asp:Label ID="Label4" runat="server" Text="State"></asp:Label></td></tr><tr><td>
<asp:TextBox ID="TextBox4" runat="server" Text="State"></asp:TextBox></td></tr><tr><td>
<asp:Label ID="Label5" runat="server" Text="Zip"></asp:Label></td></tr><tr><td>
<asp:TextBox ID="TextBox5" runat="server" Text="Zip"></asp:TextBox></td></tr><tr><td>
<asp:Label ID="Label6" runat="server" Text="Phone"></asp:Label></td></tr><tr><td>
<asp:TextBox ID="TextBox6" runat="server" Text="Phone"></asp:TextBox></td></tr><tr><td><br/><br/>
<asp:Button ID="Button1" runat="server" Text="ListJSON" /></td></tr><tr><td>
</td></tr><tr><td>
</td></tr></table></center></div>
<div id="id01"></div>
推荐答案
嗯,看起来你做了一个数组使用3个元素然后尝试通过增加索引值来添加第四个元素。不能使用数组
Well it looks like you make an array with 3 elements and then try to add a fourth by just increasing the index value. that wont work with an array
Quote:
n = obj.length + 1;
obj [n] .name = name1;
n = obj.length + 1;
obj[n].name = name1;
我猜你得到一个超出范围的数组异常( ?)
您必须使用的是推送方法
http://www.w3schools.com/jsref/jsref_push.asp [ ^ ]
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