如何上传文字和使用Httpwebrequest（Multipart / Form-Data）到Web服务器（运行I Php）的文件？ [英] How To Upload Text & Files Using Httpwebrequest (Multipart/Form-Data) To A Web Server (Running I Php) ?

问题描述

我想上传文字&从c＃中的桌面应用程序到Web服务器（运行i php）的文件，



所以我试试这段代码：



在C＃中：

  string  URL = < span class =code-string>  http：//localhost/TestUploadFile.php; 
  string  boundary =   ---- ------------------------ + DateTime.Now.Ticks.ToString（  x）; 
 WebRequest webRequest = WebRequest.Create（URL）; 
 webRequest.Method =   POST; 
 webRequest.ContentType =   multipart / form-data; boundary = + boundary; 
 
流postDataStream =  new  MemoryStream（）; 
 
  //  添加表单数据 
  string  formDataHeaderTemplate = Environment.NewLine +    -  + boundary + Environment.NewLine +   Content-Disposition：form-data; name = \{0} \;  + Environment.NewLine + Environment.NewLine +   {1}; 
  byte  [] formItemBytes = Encoding.UTF8.GetBytes（ string  .Format（formDataHeaderTemplate，< span class =code-string>  value，  valueTest））; 
 postDataStream.Write（formItemBytes， 0 ，formItemBytes.Length）; 
 
  //  添加文件数据 
 
 < span class =code-keyword> string  FilePath =  @  C：\ test \ ; 
 
  string  [] files = Directory.GetFiles（FilePath）; 
 
  for （ int  i =  0 ; i <  files.Length; i ++）
 {
 FileInfo fileInfo =  new  FileInfo（files [i]）; 
  string  fileHeaderTemplate = Environment.NewLine +   -  + boundary + Environment.NewLine +   Content-Disposition：form-data; name = \\ \\{0} \; filename = \{1} \ + Environment.NewLine +   Content-Type：application / octet-stream + Environment.NewLine + Environment.NewLine; 
  byte  [] fileHeaderBytes = Encoding.UTF8.GetBytes（ string  .Format（fileHeaderTemplate，< span class =code-string>  UploadFile，fileInfo.FullName））; 
 postDataStream.Write（fileHeaderBytes， 0 ，fileHeaderBytes.Length）; 
 
 FileStream fileStream = fileInfo.OpenRead（）; 
 
  byte  [] bufferFiles =  new   byte  [ 1024 ]; 
 
  int  bytesRead =  0 ; 
 
  while （（bytesRead = fileStream.Read（bufferFiles， 0 ，bufferFiles .Length））！=  0 ）
 {
 postDataStream.Write（buffer， 0 ，bytesRead）; 
} 
 
 fileStream.Close（）; 
} 
 
  byte  [] endBoundaryBytes = Encoding.UTF8.GetBytes（   -  + boundary +    - ）; 
 
 postDataStream.Write（endBoundaryBytes， 0 ，endBoundaryBytes.Length）; 
 
 webRequest.ContentLength = postDataStream.Length; 
 
 Stream reqStream = webRequest.GetRequestStream（）; 
 
 postDataStream.Position =  0 ; 
 
  byte  [] buffer =  new   byte  [ 1024 ]; 
 
  int  bytesRead =  0 ; 
 
  while （（bytesRead = postDataStream.Read（buffer， 0 ，缓冲区.Length））！=  0 ）
 {
 reqStream.Write（buffer， 0 ，bytesRead）; 
} 
 
 postDataStream.Close（）; 
 reqStream.Close（）; 
 
 StreamReader sr =  new  StreamReader（webRequest.GetResponse（）。GetResponseStream（））; 
  string  Result = sr.ReadToEnd（）; 
 
 MessageBox.Show（Result）; 
 

在我的WebApplication中（在php中）

 <？php  
 
  $ uploaddir  = '  upload /';  //  相对上传数据文件的位置 
 
 if（isset（$ _ FILES） ['  file'] [' < span class =code-string> tmp_name']））{
  if （is_uploaded_file（$ _ FILES ['  file'] ['  tmp_name']））{
 
  $ uploadfile  =  $ uploaddir 。 basename（$ _ FILES ['  file'] ['  name']）; 
  echo  ' 文件' 。 $ _FILES ['  file'] ['  name']。 ' 已成功上传'; 
  if （move_uploaded_file（$ _ FILES ['  file'] ['  tmp_name']，$ uploadfile））{
  echo   文件有效，并已成功移动< /跨度>; 
} 
  else  {
 print_r（$ _ FILES）; 
} 
} 
 其他 {
  echo  < span class =code-string> 上传失败!!!; 
} 
} 
 
 if（isset（$ _ POST [' 值']））{
  echo  $ _POST [' 值]; 
} 
 其他 {
  echo  '  not value'; 
} 
 

MessageBox返回上传文件的失败和表单数据的valueTest（成功表单数据）



我认为问题出在Content-Type：application / octet-stream !!!我想上传所有类型的文件（.txt，.pdf，.msg，...）



我无法理解内容类型的工作方式和我不知道边界的重要性!!!



你能帮我吗？

解决方案

uploaddir = ' upload /'; // 相对上传数据文件的位置

if（isset（

_FILES [' file'] [' tmp_name']））{
if （is_uploaded_file （

_FILES [' file'] [' tmp_name']））{

I want to upload text & files from a desktop application in c# to a web server (running i php),

So I try this code :

In C# :

string URL = "http://localhost/TestUploadFile.php";
string boundary = "----------------------------" + DateTime.Now.Ticks.ToString("x");
WebRequest webRequest = WebRequest.Create(URL);
webRequest.Method = "POST";
webRequest.ContentType = "multipart/form-data; boundary=" + boundary;

Stream postDataStream = new MemoryStream();

//adding form data
string formDataHeaderTemplate = Environment.NewLine + "--" + boundary + Environment.NewLine + "Content-Disposition: form-data; name=\"{0}\";" + Environment.NewLine + Environment.NewLine + "{1}";
byte[] formItemBytes = Encoding.UTF8.GetBytes(string.Format(formDataHeaderTemplate, "value", "valueTest"));
postDataStream.Write(formItemBytes, 0, formItemBytes.Length);

//adding file data

string FilePath = @"C:\test\";

string[] files = Directory.GetFiles(FilePath);

for(int i = 0; i < files.Length; i++)
{
    FileInfo fileInfo = new FileInfo(files[i]);
    string fileHeaderTemplate = Environment.NewLine + "--" + boundary + Environment.NewLine + "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"" + Environment.NewLine + "Content-Type: application/octet-stream" + Environment.NewLine + Environment.NewLine;
    byte[] fileHeaderBytes = Encoding.UTF8.GetBytes(string.Format(fileHeaderTemplate, "UploadFile", fileInfo.FullName));
    postDataStream.Write(fileHeaderBytes, 0, fileHeaderBytes.Length);

    FileStream fileStream = fileInfo.OpenRead();

    byte[] bufferFiles = new byte[1024];

    int bytesRead = 0;

    while ((bytesRead = fileStream.Read(bufferFiles, 0, bufferFiles.Length)) != 0)
    {
        postDataStream.Write(buffer, 0, bytesRead);
    }

    fileStream.Close();
}

byte[] endBoundaryBytes = Encoding.UTF8.GetBytes("--" + boundary + "--");

postDataStream.Write(endBoundaryBytes, 0, endBoundaryBytes.Length);

webRequest.ContentLength = postDataStream.Length;

Stream reqStream = webRequest.GetRequestStream();

postDataStream.Position = 0;

byte[] buffer = new byte[1024];

int bytesRead = 0;

while ((bytesRead = postDataStream.Read(buffer, 0, buffer.Length)) != 0)
{
    reqStream.Write(buffer, 0, bytesRead);
}

postDataStream.Close();
reqStream.Close();

StreamReader sr = new StreamReader(webRequest.GetResponse().GetResponseStream());
string Result = sr.ReadToEnd();

MessageBox.Show(Result);

In my WebApplication (in php)

<?php

$uploaddir = 'upload/'; // Relative Upload Location of data file

if(isset($_FILES['file']['tmp_name'])) {
    if (is_uploaded_file($_FILES['file']['tmp_name'])) {

        $uploadfile = $uploaddir . basename($_FILES['file']['name']);
        echo 'File '. $_FILES['file']['name']. ' uploaded successfully';
        if ( move_uploaded_file($_FILES['file']['tmp_name'], $uploadfile) ) {
        echo "File is valid, and was successfully moved ";
    }
    else {
        print_r($_FILES);
    }
}
else {
    echo "Upload Failed !!!";
}
}

if(isset($_POST['value'])) {
echo $_POST['value'];
}
else {
echo 'not value';
}

The MessageBox return "Failed" for upload files and the valueTest for form data (success for form data)

I think the problem is in the Content-Type: application/octet-stream !!! I want to upload all type of file (.txt, .pdf, .msg, ...)

I can't understand how to Content-Type work and I do not know the importance of boundary !!!

Can you help me please ?

解决方案

uploaddir = 'upload/'; // Relative Upload Location of data file if(isset(

_FILES['file']['tmp_name'])) { if (is_uploaded_file(

_FILES['file']['tmp_name'])) {

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