将php代码转换为Java或vb.net语法 [英] Convert php code to Java or vb.net syntax
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问题描述
大家好
我需要将以下代码(php base)转换为java语法或vb.net。任何的想法 ?谢谢
Hi guys
i need to convert below code ( php base ) to java syntax or vb.net . any idea ? thank you
<?php
// This class Convert Hijri date to Gregorian Date & vise versa, made by Layth A. Ibraheeim - 24-2-2011
// to test if the results are ok, please visit (http://www.oriold.uzh.ch/static/hegira.html)..
class Hijri_GregorianConvert
{
var $Day;
var $Month;
var $Year;
function intPart($floatNum)
{
if ($floatNum< -0.0000001)
{
return ceil($floatNum-0.0000001);
}
return floor($floatNum+0.0000001);
}
function ConstractDayMonthYear($date,$format) // extract day, month, year out of the date based on the format.
{
$this->Day="";
$this->Month="";
$this->Year="";
$format=strtoupper($format);
$format_Ar= str_split($format);
$srcDate_Ar=str_split($date);
for ($i=0;$iDay.=$srcDate_Ar[$i];
break;
case "M":
$this->Month.=$srcDate_Ar[$i];
break;
case "Y":
$this->Year.=$srcDate_Ar[$i];
break;
}
}
}
function HijriToGregorian($date,$format) // $date like 10121400, $format like DDMMYYYY, take date & check if its hijri then convert to gregorian date in format (DD-MM-YYYY), if it gregorian the return empty;
{
$this->ConstractDayMonthYear($date,$format);
$d=intval($this->Day);
$m=intval($this->Month);
$y=intval($this->Year);
if ($y<1700)
{
$jd=$this->intPart((11*$y+3)/30)+354*$y+30*$m-$this->intPart(($m-1)/2)+$d+1948440-385;
if ($jd> 2299160 )
{
$l=$jd+68569;
$n=$this->intPart((4*$l)/146097);
$l=$l-$this->intPart((146097*$n+3)/4);
$i=$this->intPart((4000*($l+1))/1461001);
$l=$l-$this->intPart((1461*$i)/4)+31;
$j=$this->intPart((80*$l)/2447);
$d=$l-$this->intPart((2447*$j)/80);
$l=$this->intPart($j/11);
$m=$j+2-12*$l;
$y=100*($n-49)+$i+$l;
}
else
{
$j=$jd+1402;
$k=$this->intPart(($j-1)/1461);
$l=$j-1461*$k;
$n=$this->intPart(($l-1)/365)-$this->intPart($l/1461);
$i=$l-365*$n+30;
$j=$this->intPart((80*$i)/2447);
$d=$i-$this->intPart((2447*$j)/80);
$i=$this->intPart($j/11);
$m=$j+2-12*$i;
$y=4*$k+$n+$i-4716;
}
if ($d<10)
$d="0".$d;
if ($m<10)
$m="0".$m;
return $d."-".$m."-".$y;
}
else
return "";
}
function GregorianToHijri($date,$format) // $date like 10122011, $format like DDMMYYYY, take date & check if its gregorian then convert to hijri date in format (DD-MM-YYYY), if it hijri the return empty;
{
$this->ConstractDayMonthYear($date,$format);
$d=intval($this->Day);
$m=intval($this->Month);
$y=intval($this->Year);
if ($y>1700)
{
if (($y>1582)||(($y==1582)&&($m>10))||(($y==1582)&&($m==10)&&($d>14)))
{
$jd=$this->intPart((1461*($y+4800+$this->intPart(($m-14)/12)))/4)+$this->intPart((367*($m-2-12*($this->intPart(($m-14)/12))))/12)-$this->intPart((3*($this->intPart(($y+4900+$this->intPart(($m-14)/12))/100)))/4)+$d-32075;
}
else
{
$jd = 367*$y-$this->intPart((7*($y+5001+$this->intPart(($m-9)/7)))/4)+$this->intPart((275*$m)/9)+$d+1729777;
}
$l=$jd-1948440+10632;
$n=$this->intPart(($l-1)/10631);
$l=$l-10631*$n+354;
$j=($this->intPart((10985-$l)/5316))*($this->intPart((50*$l)/17719))+($this->intPart($l/5670))*($this->intPart((43*$l)/15238));
$l=$l-($this->intPart((30-$j)/15))*($this->intPart((17719*$j)/50))-($this->intPart($j/16))*($this->intPart((15238*$j)/43))+29;
$m=$this->intPart((24*$l)/709);
$d=$l-$this->intPart((709*$m)/24);
$y=30*$n+$j-30;
if ($d<10)
$d="0".$d;
if ($m<10)
$m="0".$m;
return $d."-".$m."-".$y;
}
else
return "";
}
}
?>
推荐答案
Day ;
var
Day; var
Month ;
var
Month; var
Year ;
函数intPart(
Year; function intPart(
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