使用JQuery加载和更改此PHP脚本 [英] load and change this php script using JQuery
本文介绍了使用JQuery加载和更改此PHP脚本的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
<script src="http://code.jquery.com/jquery-1.5.min.js"></script>
<script>
$(document).ready(function () {
var $article = null;
var $business = null;
$('#category').change(function () {
var categoryName = $('#category').val();
if ($article == null) {
$article = $('<h4>Select a business you wish to view.</h4><select id="article" name="article">
<option value="0">Select A Business To View Listing</option>
</select>').appendTo('.query');
}
});
});
</script>
使用此JQuery脚本可以调整它以在从中选择对象时运行此查询第一个选择框&更改查询以包括选择Where Category =$('#category')。val();
Using this JQuery script can you adjust it to run this query upon selecting an object from the first select box & change the query to include the selection Where Category = "$('#category').val();"
<?php
$con = mysqli_connect(,,,,);
// Check connection
if (mysqli_connect_errno())
{
echo "<option>Failed to connect to MySQLi</option>" ;
}
$result = mysqli_query($con,"SELECT Bname FROM Business WHERE Category='$('#category').val();
' ");
while($row = mysqli_fetch_array($result)) {
echo "<option value='".$row['Bname']."'>".$row['Bname']."</option>";
}
// Free result set
mysqli_free_result($result);
mysqli_close($con);
?>
推荐答案
(document).ready(function(){
var
(document).ready(function () { var
article = null;
var
article = null; var
business = null;
business = null;
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