带返回传递值的JavaScript多函数。 [英] JavaScript Multiple Functions With Returns Passing Values.

问题描述

我创建了3个JavaScript函数。第一个2将返回2个值，我希望第三个函数获取这些值。

I have created 3 JavaScript Functions. The 1st 2 will return 2 values and I want the 3rd function to grab those values.

function retStartDate(){
var strStartDate = document.getElementById("from_date").value;
alert(strStartDate);

return strStartDate;

}

function retEndDate(){
var strEndDate = document.getElementById("to_date").value;
alert(strEndDate);
return strEndDate;

}

function getVaria(){

var strWsUrl = 'https://www.googleapis.com/analytics/v3/data/ga?ids=ga%3A76546294&dimensions=ga%3Asource&metrics=ga%3Ausers&filters=ga%3Asource!%3D(direct)&sort=-ga%3Ausers&start-date= retStartDate() &end-date= retEndDate() &max-results=10';

alert(strWsUrl);

return strWsUrl;

}

现在你可以看到getVaria（）有一个变量strWsUrl&因为我已经放置了返回strStartDate&的2个函数。 strEndDate如下所示。

Now you can see getVaria() has a variable strWsUrl & in that I have placed the 2 functions that return strStartDate & strEndDate as the below.

var strWsUrl = 'https://www.googleapis.com/analytics/v3/data/ga?ids=ga%3A76546294&dimensions=ga%3Asource&metrics=ga%3Ausers&filters=ga%3Asource!%3D(direct)&sort=-ga%3Ausers&start-date= retStartDate() &end-date= retEndDate() &max-results=10';

但是当我提醒我得到了以下结果时。



https://www.googleapis.com/analytics/v3/data/ga?ids=ga%3A76546294&dimensions=ga%3Asource&metrics=ga%3Ausers&filters=ga%3Asource ！％3D（直接）& sort = -ga％3Ausers& start-date = retStartDate（）& end-date = retEndDate（）& max-results = 10



但是正确的警报必须包含两个日期的开始日期和时间。结束日期。



你能猜出我做错了吗？如果是这样，请尝试发布解决方案。



谢谢&问候，

Chiranthaka。

But when I alert that I got the follwoing result.

https://www.googleapis.com/analytics/v3/data/ga?ids=ga%3A76546294&dimensions=ga%3Asource&metrics=ga%3Ausers&filters=ga%3Asource!%3D(direct)&sort=-ga%3Ausers&start-date= retStartDate() &end-date= retEndDate() &max-results=10

But the correct alert must be with two dates for start-date & end-date.

Can you someone guess what I have done wrong? If so please try to post the solution.

Thanks & regards,
Chiranthaka.

推荐答案

嗨Sampath，



它是因为你没有调用你的javascript函数。警报显示你的 strWsUrl 因为它。你可以做这样的事情。调用你的两个 javascript 以下功能

Hi Sampath,

It is because you are not calling your javascript functions.The alert shows your strWsUrl as it is.So, you can do something like this.Call two of your javascript functions like below

function getVaria(){

var strWsUrl = 'https://www.googleapis.com/analytics/v3/data/ga?ids=ga%3A76546294&dimensions=ga%3Asource&metrics=ga%3Ausers&filters=ga%3Asource!%3D(direct)&sort=-ga%3Ausers&start-date= '+ retStartDate() + '&end-date=' + retEndDate() + '&max-results=10';

alert(strWsUrl);

return strWsUrl;

}

希望这个帮助： - ）

Hope this help :-)

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