textBox失去对嵌套Gridview的关注 [英] textBox Lose focus on nested Gridview

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本文介绍了textBox失去对嵌套Gridview的关注的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有两个嵌套的Gridview,父级用于Posts,Child用于评论,我想用时间间隔更新帖子和评论,所以我使用的是asp.net计时器,我的问题是在第一个Gridview丢失的TextBox当计时器Tick,我搜索了很多,可能的解决方案是从UpdatePanel中放置文本框,但在这种情况下我不能放出textBox。请帮帮我这里是我的代码



I have two nested Gridview that parent is for Posts and Child is for Comments, i want to update Post and Comments with a Time Interval so Im using an asp.net Timer, my problem is a TextBox that is in First Gridview lose focus when timer Tick, i Searched the web a lot, Possible solution was the put textbox out of UpdatePanel but in this situation i cant put out the textBox. please help me here is my code

<asp:ScriptManager ID="ScriptManager1" runat="server"></asp:ScriptManager>

    <asp:Timer ID="Timer1" Interval="10000" OnTick="Timer1_Tick" runat="server"></asp:Timer>

    <asp:UpdatePanel ID="UpdatePanel1" UpdateMode="Conditional" runat="server">

        <Triggers>
            <asp:AsyncPostBackTrigger ControlID="Timer1" EventName="Tick" />
        </Triggers>

        <ContentTemplate>

            <%--post GridView--%>
            <asp:GridView ID="posts" runat="server">
                <Columns>
                    <asp:TemplateField>
                        <ItemTemplate>

                            <%--Comments Gridview--%>
                            <asp:GridView ID="comments" runat="server"></asp:GridView>


                            <%--a Textbox and bUtton For sending new Comment--%>
                            <asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
                            <asp:Button ID="Button1" runat="server" Text="Button" />
                        </ItemTemplate>




                    </asp:TemplateField>
                </Columns>


            </asp:GridView>


        </ContentTemplate>
    </asp:UpdatePanel>










 protected void Timer1_Tick(object sender, EventArgs e)
{
    posts.DataSource = GetData();
    posts.DataBind();
}

推荐答案

使用

if(!ispostback)

{

}

页面加载事件....希望它能帮到你
using
if(!ispostback)
{
}
on page load event.... hope it will help u


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