订单号的递归字母表 [英] recursive alphabet for order number
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问题描述
美好的一天专家!
当订单号达到500时,我正试图为我的订单号制作一个递归字母(但在我的测试中,我将其设置为1)。下面的代码从A - Z到AA工作正常,但是当涉及AB时,它显示AA并将ornumber重置为正确的。我的代码出了什么问题?
Good day experts!
i'm trying to make a recursive alphabet for my ORDER NUMBER when order number reaches 500 (but in my test i set it to 1).The code below are working fine from A - Z upto AA,but when it comes to AB,it display AA and reset the ornumber to one which is right. What is wrong with my code?
Private Sub generateORNumber()
Dim con As New SqlConnection(ConnectString())
Dim cd As New SqlCommand
Dim lrd As SqlDataReader
Try
con.Open()
cd.Connection = con
cd.CommandText = "SELECT count(ornumber) as co,AlphabetID FROM BlueRoomTransactions group by AlphabetID"
lrd = cd.ExecuteReader()
While lrd.Read()
ornum = Convert.ToString(lrd("co"))
alpID = Convert.ToString(lrd("AlphabetID"))
End While
Catch ex As Exception
Finally
con.Close()
End Try
ornum = ornum + 1
totalORNUM2 = ornum - 1
txtORNumber.Text = "OR" & Date.Today.ToString("MMddyy") & alphRecursive().ToString & ornum.ToString.PadLeft(4, "0")
End Sub
Private Function alphRecursive() As String
Dim alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray()
If ornum > 1 Then
alpID += 1
c = alpID
''Reset ornum to zero(0) and add another alphabet on the existing string like 'AA,AB' after it reaches the designated ornum like 1
If c >= alphabet.Length Then
ornum = ornum - totalORNUM2
c = 0
Return alphRecursive(c \ alphabet.Length) & alphabet(c Mod alphabet.Length)
Else
ornum = ornum - totalORNUM2
Return "" & alphabet(c Mod alphabet.Length)
End If
Else
Return "" & alphabet(c Mod alphabet.Length)
End If
End Function
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