我们如何将类对象作为XML传递给WCF REST后的METHOD？ [英] How can we pass the class object as XML to WCF REST post METHOD?

问题描述

我有一个场景，我需要将类对象作为输入发送到WCF REST方法，如下所示。

I have a scenario where I need to send the class object to the WCF REST method as input as given below.

[OperationContract]
        [WebInvoke(Method = "POST", UriTemplate = "/InsertContact", ResponseFormat = WebMessageFormat.Xml,
          RequestFormat = WebMessageFormat.Xml, BodyStyle = WebMessageBodyStyle.Wrapped)]
        int InsertContact(ContactType objContactType);

在提琴手中获得以下错误

Getting the below error in the Fiddler

<pre lang="xml"><Fault xmlns="http://schemas.microsoft.com/ws/2005/05/envelope/none"><Code><Value>Receiver</Value><Subcode><Value xmlns:a="http://schemas.microsoft.com/net/2005/12/windowscommunicationfoundation/dispatcher">a:InternalServiceFault</Value></Subcode></Code><Reason><Text xml:lang="en-US">Error in deserializing body of request message for operation 'InsertContact'. OperationFormatter encountered an invalid Message body. Expected to find node type 'Element' with name 'InsertContact' and namespace 'http://tempuri.org/'. Found node type 'Element' with name 'ContactType' and namespace ''</Text></Reason><Detail><ExceptionDetail xmlns="http://schemas.datacontract.org/2004/07/System.ServiceModel" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"><HelpLink i:nil="true"/><InnerException><HelpLink i:nil="true"/><InnerException i:nil="true"/><Message>OperationFormatter encountered an invalid Message body. Expected to find node type 'Element' with name 'InsertContact' and namespace 'http://tempuri.org/'. Found node type 'Element' with name 'ContactType' and namespace ''</Message><StackTrace>   at System.ServiceModel.Dispatcher.DataContractSerializerOperationFormatter.DeserializeBody(XmlDictionaryReader reader, MessageVersion version, String action, MessageDescription messageDescription, Object[] parameters, Boolean isRequest)&#xD;
   at System.ServiceModel.Dispatcher.OperationFormatter.DeserializeBodyContents(Message message, Object[] parameters, Boolean isRequest)&#xD;
   at System.ServiceModel.Dispatcher.OperationFormatter.DeserializeRequest(Message message, Object[] parameters)</StackTrace><Type>System.Runtime.Serialization.SerializationException</Type></InnerException><Message>Error in deserializing body of request message for operation 'InsertContact'. OperationFormatter encountered an invalid Message body. Expected to find node type 'Element' with name 'InsertContact' and namespace 'http://tempuri.org/'. Found node type 'Element' with name 'ContactType' and namespace ''</Message><StackTrace>   at System.ServiceModel.Dispatcher.OperationFormatter.DeserializeRequest(Message message, Object[] parameters)&#xD;
   at System.ServiceModel.Dispatcher.DemultiplexingDispatchMessageFormatter.DeserializeRequest(Message message, Object[] parameters)&#xD;
   at System.ServiceModel.Dispatcher.UriTemplateDispatchFormatter.DeserializeRequest(Message message, Object[] parameters)&#xD;
   at System.ServiceModel.Dispatcher.CompositeDispatchFormatter.DeserializeRequest(Message message, Object[] parameters)&#xD;
   at System.ServiceModel.Dispatcher.DispatchOperationRuntime.DeserializeInputs(MessageRpc&amp; rpc)&#xD;
   at System.ServiceModel.Dispatcher.DispatchOperationRuntime.InvokeBegin(MessageRpc&amp; rpc)&#xD;
   at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage5(MessageRpc&amp; rpc)&#xD;
   at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage41(MessageRpc&amp; rpc)&#xD;
   at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage4(MessageRpc&amp; rpc)&#xD;
   at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage31(MessageRpc&amp; rpc)&#xD;
   at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage3(MessageRpc&amp; rpc)&#xD;
   at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage2(MessageRpc&amp; rpc)&#xD;
   at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage11(MessageRpc&amp; rpc)&#xD;
   at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage1(MessageRpc&amp; rpc)&#xD;
   at System.ServiceModel.Dispatcher.MessageRpc.Process(Boolean isOperationContextSet)</StackTrace><Type>System.ServiceModel.CommunicationException</Type></ExceptionDetail></Detail></Fault>

I想让我的REST API接受JSON或XML请求dep结束于client.Do我需要在WebInvoke属性或web.config中设置此属性吗？



任何人都可以帮我这个吗？

I want to make my REST API to accept either JSON or XML request depending on the client.Do I need to set this property in the WebInvoke attribute or in the web.config ?

Can anyone help me regarding this ?

推荐答案

我通常使用DataContractSerializer序列化对象以获取实际的xml。

其次我使用BodyStyle = WebMessageBodyStyle.Bare



public static string Serialize（ContactType obj）

{

using（MemoryStream memoryStream = new MemoryStream（））

{

使用（StreamReader reader = new StreamReader（memoryStream））

{

DataContractSerializer serializer = new DataContractSerializer（obj.GetType（）） ;

serializer.WriteObject（memoryStream，obj）;

memoryStream.Position = 0;

return reader.ReadToEnd（）;

} < br $>
}

}



public static ContactType反序列化（字符串xml）

{

使用（Stream stream = new MemoryStream（））

{

byte [] data = System.Text.Encoding.UTF8.GetBytes（ xml）;

stream.Write（data，0，data.Length）;

stream.Position = 0;

DataContractSerializer deserializer = new DataContractSerializer（typeof（ContactType））;

return（ContactType）deserializer.ReadObject（stream）;

}

}

i normally serialize the object with DataContractSerializer to get the actual xml.
secondly i use BodyStyle = WebMessageBodyStyle.Bare

public static string Serialize(ContactType obj)
{
using (MemoryStream memoryStream = new MemoryStream())
{
using (StreamReader reader = new StreamReader(memoryStream))
{
DataContractSerializer serializer = new DataContractSerializer(obj.GetType());
serializer.WriteObject(memoryStream, obj);
memoryStream.Position = 0;
return reader.ReadToEnd();
}
}
}

public static ContactType Deserialize(string xml)
{
using (Stream stream = new MemoryStream())
{
byte[] data = System.Text.Encoding.UTF8.GetBytes(xml);
stream.Write(data, 0, data.Length);
stream.Position = 0;
DataContractSerializer deserializer = new DataContractSerializer(typeof(ContactType));
return (ContactType)deserializer.ReadObject(stream);
}
}

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