如何生成100个随机数 [英] How Do I Generate 100 Random Numbers

问题描述

我正在尝试在列表框中生成100个随机数。我怎么能用我的代码呢？

I'm trying generate 100 random numbers in a listbox. How can I do that with my code?

public partial class Form1 : Form
    {
        
        #region Declaration
        
        int[] die;
        int Total;
        int[] i_Array = new int[5];
        
        
        Random rand;

        
        List<int> diceresults = new List<int>();
        List<picturebox> dices= new List<picturebox>();
        BindingList<object> listBox = new BindingList<object>();

        
        MyResult MR = new MyResult();

        
        #endregion

        
        #region Initialization

        public Form1()
        {
            
            InitializeComponent();
            dices.Add(picbxDie1);
            dices.Add(picbxDie2);
        }

        private void Form1_Load(object sender, EventArgs e)
        {
           
            die = new int[2] { 0, 0 };
            rand = new Random();
        }
        #endregion

        
        #region Private Methods
        private void btnWrite_Click(object sender, EventArgs e)
        {
                rolldice();
        }

        private void rolldice()
        {
            
            Total = 0;

            
            diceresults.Clear();
            
            
            for (int i = 1; i < die.Length; i++)
            {                
                diceresults.Add(rand.Next(1, 7))
                int imageNumber = diceresults[i] - 1 ;
                dices[i].Image = this.imageList1.Images[imageNumber];With Value
                
                Total += diceresults[i];
                txtResult.Text = Total.ToString(); 
            }
            
            this.txtResult.Focus();
            listBox1.Items.Add("Roll A Sum of  " + txtResult.Text);
            
        }

推荐答案

任何努力？



您可以生成1到1000之间的100个数字，如下所示：

Any effort?

You can generate 100 numbers between 1 and 1000 like this:

var randomNumbers = new List<int>();
var random = new Random(0);
for (var count = 0; count < 100; count++)
{
    randomNumbers.Add(random.Next(1, 1000));
}

或者使用相同的列表/逻辑将其绑定到UI元素。

Or use the same list/logic to bind it to a UI element.

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