DataTable列到图表(图表) [英] DataTable column to chart (graph)

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本文介绍了DataTable列到图表(图表)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个DataTable如下:



new |老| New_1 |情节



2.1 | 1.1 | 4.3 | 0.60



0.4 | 1.2 | 2.1 | 0.12



3.1 | 2.3 | 3.2 | 0.29

我想绘制图表:1new vs plot,Old vs plot,new_1 vs plot1并将每个图保存为图像,从而为每列创建多个图表图像。



我想使用列索引,绘图列的索引是固定的。



我想如果我能够保存图像每次使用不同的名称并循环列索引,我将能够为每列生成图表。





I have a DataTable as the following:

new | Old | New_1| plot

2.1 | 1.1 | 4.3 | 0.60

0.4 | 1.2 | 2.1 | 0.12

3.1 | 2.3 | 3.2 | 0.29
I want to plot chart's with: 1new vs plot , Old vs plot, new_1 vs plot1 and save each of plots as images thus creating multiple chart images one for each column.

I want to use column index, the index of plot column is fixed.

I think if I am able to save image with different names each time and loop the column index ,I will be able to generate charts for each column.


for (int g = 0; g < resultDt.Columns.Count-1; g++)

// (resultDt.Columns.Count-1) last column is plot

{

Chart chart = new Chart(); chart.DataSource = resultDt;

chart.Width = 800;

chart.Height = 550;

//create serie...

  Series serie1 = new Series();
serie1.Name = "Serie1";

 serie1.Color = Color.FromArgb(112, 255, 200);

   serie1.BorderColor = Color.FromArgb(164, 164, 164);

   serie1.ChartType = SeriesChartType.Line;


  serie1.XValueMember = resultDt.Columns[0].ColumnName;

   serie1.YValueMembers = "plot";

    chart.Series.Add(serie1);


//create chartareas...
ChartArea ca = new ChartArea();
ca.Name = "ChartArea1";
ca.BackColor = Color.White;
ca.BorderColor = Color.FromArgb(26, 59, 105);
ca.BorderWidth = 0;
ca.BorderDashStyle = ChartDashStyle.Solid;
ca.AxisX = new Axis();
ca.AxisY = new Axis();
//ChartArea 
ca = new ChartArea("main");

ca.BackColor = System.Drawing.Color.FromArgb(64, System.Drawing.Color.White);

chart.ChartAreas.Add(ca);

//databind... 
chart.DataBind();

//save result... 
chart.SaveImage(@"C:\myChart.png", ChartImageFormat.Png);

}

推荐答案

chart.SaveImage(@"C:\Matlab\" + (g).ToString() + ".png", ChartImageFormat.Png);


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