如何在asp.net c＃网站的datagridview中打开图像onClick [英] How to open an image onClick in datagridview in asp.net c# website
本文介绍了如何在asp.net c＃网站的datagridview中打开图像onClick的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
<％@ Page 语言 = C＃ AutoEventWireup = true CodeBehind = gridcheck.aspx.cs 继承 = Website.gridcheck ％>
< ！DOCTYPE html PUBLIC - // W3C // DTD XHTML 1.0 Transitional // EN http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd >
< html xmlns = http://www.w3.org/1999 / xhtml >
< head runat = server >
< title > GridView < / title >
< / head >
< body >
< 表单 id = form1 runat = server >
< div >
< asp：GridView ID = GridView1 runat = server AutoGenerateColumns = False
< span class =code-attribute> DataSourceID = SqlDataSource1 AllowPaging = True BorderStyle = 无
CellSpacing = 4 GridLines = 无 HorizontalAlign = 中心 ShowHeader = False
style = text-align：left >
< span class =code-keyword>< 列 >
< asp：ImageField DataImageUrlField = img
DataImageUrlFormatString = 〜/ uploads / {0} ControlStyle-Height = 200px ControlStyle-Width = 200px >
< / asp：ImageField >
< / Columns >
< EmptyDataRowStyle HorizontalAlign = 中心 VerticalAlign = 中间 / >
< / asp：GridView >
< asp：SqlDataSource ID = SqlDataSource1 runat = server
ConnectionString = <跨度类= 代码pagedirective><％ $的ConnectionStrings：RoughConnectionString <跨度类= 代码pagedirective>％> <跨度类= 代码-attribute>
SelectCommand = SELECT [img] FROM [uploads] > < / asp：SqlDataSource >
< / div >
< / form >
< / body >
< / html >
解决方案
的ConnectionStrings：RoughConnectionString <跨度类= 代码pagedirective>％> <跨度类= 代码属性> <跨度class =code-attribute>
SelectCommand = SELECT [img] FROM [uploads] > < / asp：SqlDataSource >
< span class =code-keyword>< / div >
< / form >
< / body >
< / html > < /跨度>
<%@ Page Language="C#" AutoEventWireup="true" CodeBehind="gridcheck.aspx.cs" Inherits="Website.gridcheck" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title>GridView</title>
</head>
<body>
<form id="form1" runat="server">
<div>
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False"
DataSourceID="SqlDataSource1" AllowPaging="True" BorderStyle="None"
CellSpacing="4" GridLines="None" HorizontalAlign="Center" ShowHeader="False"
style="text-align: left">
<Columns>
<asp:ImageField DataImageUrlField="img"
DataImageUrlFormatString="~/uploads/{0}" ControlStyle-Height="200px" ControlStyle-Width="200px">
</asp:ImageField>
</Columns>
<EmptyDataRowStyle HorizontalAlign="Center" VerticalAlign="Middle" />
</asp:GridView>
<asp:SqlDataSource ID="SqlDataSource1" runat="server"
ConnectionString="<%$ ConnectionStrings:RoughConnectionString %>"
SelectCommand="SELECT [img] FROM [uploads]"></asp:SqlDataSource>
</div>
</form>
</body>
</html> 解决方案
ConnectionStrings:RoughConnectionString %>" SelectCommand="SELECT [img] FROM [uploads]"></asp:SqlDataSource> </div> </form> </body> </html>
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