如何将行转置为列 [英] How to transpose row to column

问题描述

SOHeaderId	SODetailId
11004	        100030
11004	        100031
11004	        100032
11004	        100033
11004	        100034
11004	        100035
11004	        100036
11005           100037
11005           100038
11005           100039
11005           100040
11006           100041
11006           100042
11006           100058
11006           100078
wanted it as

SOHeaderId     SODetailId
11004           100030,100031,100032,100033,100034,100035,100036
11005           100037,100038,100039,100040
11006           100041,100042,100058,100078

WITH THE help of SQL Query only

我已经尝试过谷歌，但不能解决它。

I have already tried on google, but not able to solve it.

推荐答案

您不需要将行转置为列。您需要将[SODeaderId]列的不同[SODeaderId]连接到由逗号分隔的字符串中。最简单的方法之一是使用 XML PATH（''）。



您的查询应该是这样的：

You don't need to transpose rows into columns. You need to concatenate [SODetailId] column values by distinct [SOHeaderId] into a string separated by commas. One of the simplest ways to do this is to use XML PATH('').

Your query should be something like this:

SELECT DISTINCT [SOHeaderId],
                STUFF((SELECT ',' + CAST([SODetailId] AS VARCHAR(10))
                       FROM   [TableName] t1
                       WHERE  t1.[SOHeaderId] = t2.[SOHeaderId]
                       FOR XML PATH('')), 1, 1, '')
FROM   [TableName] t2

我假设[SODetailId]的数据类型是 INT ，所以我将它转换为 VARCHAR（10）。



参考文献：

1. STUFF AND FOR XML PATH for String Concatenation [ ^ ]

2. 使用FOR XML PATH和STUFF来加强 [ ^ ]

I am assuming that the data type of [SODetailId] is INT, so I am casting it to VARCHAR(10).

References:
1. STUFF AND FOR XML PATH for String Concatenation[^]
2. Using FOR XML PATH and STUFF to CONCATENATE[^]

这篇关于如何将行转置为列的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！