如何从aspx页面中删除无效表达式')'错误 [英] How can I remove the Invalid expression ')' error from aspx page
本文介绍了如何从aspx页面中删除无效表达式')'错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
< asp:HyperLink ID =Log_OutOnLoad =GoToLoginPage(); runat =server> [Log Out]
<asp:HyperLink ID="Log_Out" OnLoad="GoToLoginPage();" runat="server">[Log Out]
推荐答案
您好Pramod_007,您正在使用服务器控件,因此您必须在那里调用服务器事件:
Hi Pramod_007, you're using a server control, so you must call to a server event there:
<asp:hyperlink id="Log_Out" onload="GoToLoginPage" runat="server" xmlns:asp="#unknown">
</asp:hyperlink>
所以,在你的代码背后(C#,在这种情况下)你会有这样的东西:
So, in your code behind (C#, in this case) you will have something like this:
private void GoToLoginPage(object sender, EventArgs e)
{
//Redirect to your desired page
}
你的问题很简单,但我认为这就是你要找的。
希望它有所帮助。
Your question is so simple, but I think that is it that you looking for.
Hope it helps, any way.
>
尝试< asp:hyperlink id =Log_Outonload =return GoToLoginPage(); runat =serverxmlns:asp =#unknown> [Log Out]< / asp:hyperlink>
< asp:hyperlink id =Log_Outonload =GoToLoginPage(); runat =serverxmlns:asp =#unknown> [退出]
修改如下
< asp:hyperlink id =Log_Outonload =GoToLoginPagerunat =server> [退出]
<asp:hyperlink id="Log_Out" onload="GoToLoginPage();" runat="server" xmlns:asp="#unknown">[Log Out]
Modify as below
<asp:hyperlink id="Log_Out" onload="GoToLoginPage" runat="server">[Log Out]
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