从段落中查找特定文本。 [英] Finding particular text from Paragraph.

问题描述

示例文本：



医疗保健提供商正处于新兴医疗保健范式转变。随着65岁以上人口的增加和长期护理患者人数的增加，慢性病的管理现已成为现实，几乎没有争论。强调疾病管理正在转向协调慢性病的护理;这是一个乐观的观察结果。预计2060年人口增长的人口现实将超过9000万。这将占总人口的近22％（美国人口普查，2013年）。



我需要上一段中此文本的医疗保健计数值（即该单词存在多少次）

解决方案

学会自己动手：计算单词出现的次数字符串 [ ^ ]

有很多方法可以做到这一点（这里描述的大多数方法：计算字符串中的行数 [ ^ ]可以适应它。）

但是，最简单的阅读可能是：

  int  count = Regex.Matches（inputString， 保健 ）。计数; 

如果你没有使用大量数据，或经常这样做，那可能就是我要去的那个。

查看此链接



http：// msdn.microsoft.com/en-us/library/bb546166.aspx [ ^ ]



http ：//www.dotnetperls.com/string-occurrence [ ^

Sample Text:

"health-care providers are in the midst of a burgeoning health-care paradigm shift. As the population over age 65 increases and the number of patients in long-term care climbs, the management of chronic disease is now a reality that few debate. Emphasis on disease management is shifting to coordination of care for chronic disease; this is an optimistic observation. The demographic realities of an increasing older population are expected to eclipse 90 million in 2060. This will be nearly 22% of the total population (U.S. Census, 2013)."

I need the "health-care" count value of this text in the above paragraph(ie.How many times the word is present)

解决方案

Learn to do it yourself: Count Occurrences of a Word in a String[^]

There are a lot of ways to do this (most of the ways described here: Counting Lines in a String[^] can be adapted to do it).
But, the simplest to read is probably:

int count = Regex.Matches(inputString, "health-care").Count;

And if you aren't using large amounts of data, or doing it often, that's probably the one I'd go for.

check this link

http://msdn.microsoft.com/en-us/library/bb546166.aspx[^]

http://www.dotnetperls.com/string-occurrence[^]

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