最简单的解析JSON字符串的方法 [英] simplest way to parse JSON string

问题描述

我如何可以浏览JSON字符串从一个键，另一个嵌套键和获得的价值？我有以下字符串

  {数据：{current_condition：[{cloudcover：75，
            湿度：29，
            observation_time：下午7点59分，
            precipMM：0.0，
            pressure：1011，
            TEMP_C：19，
            temp_F：67，
            可见性：16，
            天气code：116，
            weatherDesc：[{值：晴间多云}]，
            weatherIconUrl：[{值：http://www.worldweatheronline.com/images/wsymbols01_png_64/wsymbol_0002_sunny_intervals.png}]，
            winddir16Point：N，
            winddirDegree：350，
            windspeedKmph：26，
            windspeedMiles：16
          }]，
      要求：[{查询：01801，
            类型：拉链code
          }]，
      天气预报：[{日期：2011-05-09，
            precipMM：0.0，
            tempMaxC：19，
            tempMaxF：65，
            tempMinC：10，
            tempMinF：50，
            天气code：113，
            weatherDesc：[{值：艳阳天}]，
            weatherIconUrl：[{值：的http：//www/images/wsymbols01_png_64/wsymbol_0001_sunny.png}]，
            winddir16Point：西北偏北，
            winddirDegree：348，
            winddirection：西北偏北，
            windspeedKmph：24，
            windspeedMiles：15
          }，
          {日期：2011-05-10，
            precipMM：0.1，
            tempMaxC：13，
            tempMaxF：56，
            tempMinC：12，
            tempMinF：53，
            天气code：122，
            weatherDesc：[{值：雷雨}]，
            weatherIconUrl：[{值：的http：//www/images/wsymbols01_png_64/wsymbol_0004_black_low_cloud.png}]，
            winddir16Point：东北偏北，
            winddirDegree：12，
            winddirection：东北偏北，
            windspeedKmph：31，
            windspeedMiles：19
          }
        ]
    }}
 

所以，我回答我的问题： 如果别人想快速获得价值：这就是我一直在寻找

 的JSONObject J =新的JSONObject（strResponse）;

字符串weatherDesc = jObject.getJSONObject("data").getJSONArray("weather").getJSONObject(0).getJSONAr­ray("weatherDesc").getJSONObject(0).getString("value");
 

解决方案

有在pretty的太多任何语言的JSON库。如果你提出一个，我也许可以给你点的东西。

在此期间，这里有几个：

• Perl的JSON库
• Python的是内置的
• 的Javascript序列化及其在JSON对象所以它的超级容易
• C＃库 - 也看到<一href="http://stackoverflow.com/questions/802766/c-parsing-json-formatted-data-into-nested-hashtables">C# - 解析JSON格式的数据转换成嵌套的哈希表
• 下面是Android的JSON参考

等。我提出一个快速谷歌为您所选择的语言。

How can I navigate JSON string from one key to another nested key and get the value? I have the following string

{ "data" : { "current_condition" : [ { "cloudcover" : "75",
            "humidity" : "29",
            "observation_time" : "07:59 PM",
            "precipMM" : "0.0",
            "pressure" : "1011",
            "temp_C" : "19",
            "temp_F" : "67",
            "visibility" : "16",
            "weatherCode" : "116",
            "weatherDesc" : [ { "value" : "Partly Cloudy" } ],
            "weatherIconUrl" : [ { "value" : "http://www.worldweatheronline.com/images/wsymbols01_png_64/wsymbol_0002_sunny_intervals.png" } ],
            "winddir16Point" : "N",
            "winddirDegree" : "350",
            "windspeedKmph" : "26",
            "windspeedMiles" : "16"
          } ],
      "request" : [ { "query" : "01801",
            "type" : "Zipcode"
          } ],
      "weather" : [ { "date" : "2011-05-09",
            "precipMM" : "0.0",
            "tempMaxC" : "19",
            "tempMaxF" : "65",
            "tempMinC" : "10",
            "tempMinF" : "50",
            "weatherCode" : "113",
            "weatherDesc" : [ { "value" : "Sunny" } ],
            "weatherIconUrl" : [ { "value" : "http://www/images/wsymbols01_png_64/wsymbol_0001_sunny.png" } ],
            "winddir16Point" : "NNW",
            "winddirDegree" : "348",
            "winddirection" : "NNW",
            "windspeedKmph" : "24",
            "windspeedMiles" : "15"
          },
          { "date" : "2011-05-10",
            "precipMM" : "0.1",
            "tempMaxC" : "13",
            "tempMaxF" : "56",
            "tempMinC" : "12",
            "tempMinF" : "53",
            "weatherCode" : "122",
            "weatherDesc" : [ { "value" : "Overcast" } ],
            "weatherIconUrl" : [ { "value" : "http://www/images/wsymbols01_png_64/wsymbol_0004_black_low_cloud.png" } ],
            "winddir16Point" : "NNE",
            "winddirDegree" : "12",
            "winddirection" : "NNE",
            "windspeedKmph" : "31",
            "windspeedMiles" : "19"
          }
        ]
    } }

So I answer my own question: In case someone else want to get value quickly: This is what I was looking for.

JSONObject j = new JSONObject(strResponse);

String weatherDesc = jObject.getJSONObject("data").getJSONArray("weather").getJSONObject(0).getJSONAr­ray("weatherDesc").getJSONObject(0).getString("value");

解决方案

There are JSON libraries in pretty much any language. If you suggest one, I might be able to point you to something.

In the meantime, here are a few:

• Perl JSON library
• Python's is built in
• Javascript serializes its objects in JSON so it's super easy
• C# library -- also see C# - parsing json formatted data into nested hashtables
• Here's the Android JSON reference

And so on. I suggest a quick google for the language of your choice.

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